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vladimir1956 [14]
3 years ago
13

A. Find the slope of the line that passes through the two points: (4, 4) and (0, 2).

Mathematics
2 answers:
Vladimir [108]3 years ago
6 0

Answer:

Slope (m)= -2/-4= 0.5

-2/-4 as fraction form

or

0.5 as decimal form

Step-by-step explanation:

slope (m)= -2/-4= 0.5

points belong to an increasing linear function

equation: y=0.5x+2

Oksanka [162]3 years ago
5 0

Answer:

The slope is -2/-4 or simplified -1/-2

Step-by-step explanation:

First you would use the slope formula which is m=(y2-y1)/(x2-x1).

m = 2-4/0-4 which equals -2/-4

Then simplify to get -1/-2

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Find the slope of the line that passes through (-49, 68) and (-43, 67).
Arte-miy333 [17]

Answer:

Slope = 67 - 68 / -43 + 49

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Hope this helps

8 0
3 years ago
Express answer in exact form.
bazaltina [42]
The answer is 5.13 in²

Step 1. Calculate the diameter of the circle (d).
Step 2. Calculate the radius of the circle (r).
Step 3. Calculate the area of the circle (A1).
Step 4. Calculate the area of the square (A2).
Step 5. Calculate the difference between two areas (A1 - A2) and divide it by 4 (because there are total 4 segments) to get <span>the area of one segment formed by a square with sides of 6" inscribed in a circle.
</span>
Step 1:
The diameter (d) of the circle is actually the diagonal (D) of the square inscribed in the circle. The diagonal (D) of the square with side a is:
D = a√2            (ratio of 1:1:√2 means side a : side a : diagonal D = 1 : 1 : √2)
If a = 6 in, then D = 6√2 in.
d = D = 6√2 in

Step 2.
The radius (r) of the circle is half of its diameter (d):
r = d/2 = 6√2 / 2 = 3√2 in

Step 3.
The area of the circle (A1) is:
A = π * r²
A = 3.14 * (3√2)² = 3.14 * 3² * (√2)² = 3.14 * 9 * 2 = 56.52 in²

Step 4.
The area of the square (A2) is:
A2 = a²
A2 = 6² = 36 in²

Step 5:
(A1 - A2)/4 = (56.52 - 36)/4 = 20.52/4 =  5.13 in²
6 0
2 years ago
Read 2 more answers
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Now plug in the value of θ for cosine:

cos (2π/3) = -1/2

And tangent:

tan (2π/3) = -√3/3
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3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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