Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
Answer:
Add all and you will get the answer...........
Answer:
Independent: Amount of hours she works
Dependent: Amount of money she makes
Step-by-step explanation:
The independent variable is the part of the equation that changes. In this case the only thing that changes is how long she works, the amount of money she charges and what she is doing does not change.
The dependent variable is what you measure in the equation. In this case, the amount of money she makes <em>depends</em><em> </em><em>on</em> the amount of time she works.
Probally d most likely because if you know what the deer looks like it is orange and white spots so it is more manipulating the light from the leaves. If im wrong then its A
Answer:
57.5 mi
Step-by-step explanation:
1 in = 5 mi
11.5 × 5 = 57.5 mi
