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baherus [9]
4 years ago
10

The function y = 8.5(1.1)x models the population in thousands of a town where x is the number of years after 2000. What will be

the town's population in 2007? Give the answer to two decimal places.

Mathematics
1 answer:
nikdorinn [45]4 years ago
6 0

Answer:

The population will be at 65.45 in 2007.

Step-by-step explanation:

I graphed the equation below to find the answer.

If this answer is correct, please make me Brainliest!

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I WILL GIVE BRAINLIST IF ALL ANSWERED CORRECTLY
pentagon [3]

Answer:

The length of the track is approximately 51.7 ft

The track has three sides of the square and the distance round a half of a complete circle

Step-by-step explanation:

The given track shape and measurements are;

The shape on the left side of the track  = Square

The shape on the right side of the track  = Half circle

The area of the square on the the left side of the track  = 128 square feet

Therefore, from the area, A, of a square of side length, s, which is s × s, and letting the side length of the square = s, we have;

Area of the square portion of the track = s × s = s² = 128 ft²

Therefore, s = √(128 ft²) = 8·√(2) ft.

Whereby the side length of the square is bounded by the diameter of the half circle, we have;

Length of the diameter of the half circle = s = 8·√(2) ft.

The length of the perimeter of the half circle = π·D/2 = π × 8·√(2)/2 = π × 4·√(2) ≈ 17.77 ft.

The perimeter of the track, which is the length of the track is made up of the three sides of the square opposite to the half circle and the circumference of the half circle.

Therefore;

The length of the track = 3 × 8·√(2) ft + π × 4·√(2) ft. = 4·√2×(π+6) ≈ 51.7 ft

The length of the track ≈ 51.7 ft

Which gives;

The track has three sides of the square and the distance round a half of a complete circle.

4 0
3 years ago
What is the difference in speed between two cars when one traveled 175 km in 4 hours and the other traveled the same distance in
vovangra [49]
<h3>Given :</h3>
  • Distance = 175
  • Time 1 = 4 hours

\\  \\

<h3>To find:</h3>
  • Different between two speeds when distance is same.

\\  \\

<h3>Solution:</h3>

<u>Part</u><u> </u><u>1</u><u> </u><u>:</u>

In first part we will find speed 1 in which time is 4 hours

we know:-

\bigstar \boxed{ \rm speed =  \frac{distance}{time} }

So:-

\dashrightarrow\sf speed_1 =  \dfrac{distance}{time_1}

\\  \\

\dashrightarrow\sf speed_1 =  \dfrac{175}{4}

\\  \\

\dashrightarrow\bf speed_1 =  43.75 \: km {h}^{ - 1}

<u>Part 2</u>

In first part we will find speed 2 in which time is 3 hours

Again:

\bigstar \boxed{ \rm speed =  \frac{distance}{time} }

\\  \\

\dashrightarrow\sf speed_2 =  \dfrac{distance}{time_2}

\\  \\

\dashrightarrow\sf speed_2 =  \dfrac{175}{3}

\\  \\

\dashrightarrow\bf speed_2 = 58.33kmh^{-1}

\\  \\

<u>Part 3</u>

In this part we will find different between speed 1 and speed 2

\bigstar  \boxed{\rm Difference = speed_2 - speed_1}

\\  \\

So :

\dashrightarrow\sf Difference = speed_2 - speed_1 \\

\\  \\

\dashrightarrow\sf Difference =58.33 - 43.75\\

\\  \\

\dashrightarrow\bf Difference =14.58kmh^{-1}\\

\\  \\

\therefore \underline {\textsf{\textbf{Difference in speed between two cars is \red{14.58km/h}}}}

4 0
3 years ago
One-third of the difference of a number and nine is negative fifteen. What is the number?​
Tems11 [23]

hi <3

lets call the unknown number 'x' for now and form an equation from what we know

1/3(x-9) = 15

now multiply both sides by 3

x - 9 = 45

add 9 to both sides

x = 54

hope this helps :)

3 0
3 years ago
Read 2 more answers
What is the measure of ZEKY in this figure?
zzz [600]

Answer: 104 degrees

Step-by-step explanation:

5 0
2 years ago
Any help would be great.
Ket [755]

<u>Answer:</u>

log7

<u>Step-by-step explanation:</u>

We are given the following expression in terms of log and we are to solve it:

log (14/3) + log (11/5) - log (22/15)

Just to recall, when we divide two values that have the same base, we basically subtract the exponents.

So applying this rule here to get:

(log11 - log5) + (log14 - log3) - (log22 - log15)

= log11 - log5 + log14 - log3 - log2×11 + log5.3

= loh11 - log5 + log14 - log3 - log2 - log11 + log5 + log3

Cancelling out the like terms to get:

= log14 - log2

= log 14/2

= log7

8 0
4 years ago
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