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Valentin [98]
3 years ago
15

Simplify: -4g(8g + 5)

Mathematics
1 answer:
VMariaS [17]3 years ago
4 0

Answer:

−32^2−20

Step-by-step explanation:

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Which property can you use to solve 5(6+9)
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Answer:

Step-by-step explanation:

3 0
3 years ago
Graph this parametric equation<br><br> x = 2t y = t + 5, -2 ≤ t ≤ 3
UNO [17]
We are given the following data: <span>x = 2t, y = t + 5, -2 ≤ t ≤ 3. The data is valid since there are three unknowns in this problem and that three equations would suffice to answer the problem. 

We start with the given </span>-2 ≤ t ≤ 3 then substitute y = t +5 by using the limits of the range:

at t = -2 ; y = -2 + 5 = 3
at t = 3, y = 3+5 = 8

for the second equation

at t = -2 ; x = 2*-2 =-4
at t=3; x = 2*3 = 6

we group the points based on their original corresponding t's 

(3,-4) and (8,6) we just have to connect these points along with the internal points in between. The relationship should be linear.
6 0
3 years ago
The area of the circle below is 28.26. What is the diameter?
svet-max [94.6K]
I think the answer would be 9 or 18 not really sure
3 0
3 years ago
Help me plz i need help on math i will give THANKS
atroni [7]
The answer is for your paper is 21
8 0
3 years ago
Please help!! What Find the Error and explain why it is wrong!
Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply 2\cdot x -8 by the negative sign in numerator. Step E must be \frac{2\cdot x -5}{(x+4)\cdot (x-4)}.

Second image attached

The error was done in Step C, because the student omitted the 2\cdot a \cdot b of the algebraic identity (a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}. Step C must be 5\cdot x = x^{2}+4\cdot x + 4

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply 2\cdot x -8 by the negative sign in numerator. The real numerator in Step E should be:

3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x

Hence, Step E must be \frac{2\cdot x -5}{(x+4)\cdot (x-4)}.

Second image attached

The error was done in Step C, because the student omitted the 2\cdot a \cdot b of the algebraic identity (a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}. Step C must be 5\cdot x = x^{2}+4\cdot x + 4

And further steps are described below:

Step D

x^{2}-x+4 = 0

Which according to the Quadratic Formula, represents a polynomial with complex roots. That is: (a = 1, b = -1, c = 4)

D = b^{2}-4\cdot a\cdot c

D = (-1)-4\cdot (1)\cdot (4)

D = -17 (Conjugated complex roots)

Step E

(x-0.5-i\,1.936)\cdot (x-0.5+i\,1.936) = 0

Step F

x = 0.5+i\,1.936\,\lor\,x = 0.5-i\,1.936

8 0
3 years ago
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