For a rectangle, A = LW.
A = (3x + 2)(x - 4)
A = 3x^2 - 12x + 2x - 8
A = 3x^2 -10x - 8
Answer: I think the answer would be 4+2n=60.. might be wrong though
Step-by-step explanation:
Answer:
5x^-3x-36/x-3
Step-by-step explanation:
Answer:
x = 145
Step-by-step explanation:
x and 35 are adjacent angles and are supplementary, sum to 180° , then
x + 35 = 180 ( subtract 35 from both sides )
x = 145
Have you heard the expressions "shooting fish in a barrel" or
"taking candy from a baby" ?
I've decided to take your points and try not to feel guilty about it.
A). That's it ! That's the equation, for ANY basketball on Earth.
You wrote it right there in your question.
In that equation that you wrote, the ' r ' is the initial velocity.
You said that Adam tossed it straight up, and it was going 10 meters per second
when it left his hand.
So ' r ' in the equation is +10.
The equation is:
<em>d = 10t - 5t² </em> .
It tells you how high the ball is above its tossing height after any number of seconds.
The ' t ' in the equation is the number of seconds. Any letter could have been used,
but ' t ' was cleverly selected because it stands for 'time'.
B). You want to know where it is after 0.5 second ? All you have to do is put '0.5'
into the equation wherever there's a ' t '. Do you really need somebody to do that
for you ?
Well, OK. You're being so overly generous with your points . . .
Distance = 10 t - 5 t²
Distance = 10 (0.5) - 5 (0.5)²
Distance = 5 - 5(0.25)
Distance = 5 - 1.25
<em>Distance = 3.75 meters </em>
<u>positive</u> 3.75 means <u>above</u> Adam's hand.
A thinking exercise:
-- He tossed the ball upwards at 10 meters per second.
-- Why is it not 5 meters above his hands after 0.5 second?
