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Pani-rosa [81]
2 years ago
12

Complete the puzzle by clicking on the puzzle piece that contains equivalent expression.

Mathematics
1 answer:
Liono4ka [1.6K]2 years ago
8 0

Answer:

 -5 when ...

Step-by-step explanation:

The rules of exponents can help you simplify the given product.

<h3>Rules</h3>

  (a/b)^c = (a^c)/(b^c)

  (ab)^c = (a^c)(b^c)

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

<h3>Application</h3>

  \left(\dfrac{x}{y}\right)^2(-x^2y)^3=\\\\\dfrac{x^2(-1)^3(x^2)^3y^3}{y^2}=-x^{2+2\cdot3}y^{3-2}=-x^8y

This expression does not match any of those offered.

When x=-1 and y=5, this becomes ...

  -(-1)^8(5)=\boxed{-5}

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The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15 days.
Zarrin [17]
Let the lengths of pregnancies be X
X follows normal distribution with mean 268 and standard deviation 15 days
z=(X-269)/15

a. P(X>308)
z=(308-269)/15=2.6
thus:
P(X>308)=P(z>2.6)
=1-0.995
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b] Given that if the length of pregnancy is in lowest is 44%, then the baby is premature. We need to find the length that separates the premature babies from those who are not premature.
P(X<x)=0.44
P(Z<z)=0.44
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thus the value of x will be found as follows:
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-0.05(15)=x-269
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x=-0.75+269
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<h2>Explanation:</h2>

The rational expression is given by:

E=\frac{2x^2-72}{5x^2-245} \\ \\ Factor \ out: \\ \\  E=\frac{2(x^2-36)}{5(x^2-49)} \\ \\ E=\frac{2(x-6)(x+36)}{5(x-7)(x+7)} : \ \ \ \ a^2-b^2=(a-b)(a+b)

The denominator can't be zero, therefore:

(x-7)(x+7)\neq 0 \\ \\ \\ Thus: \\ \\ \boxed{x\neq 7 \ and x \neq -7}

Finally,<em> the values of x that make the rational expression undefined are </em>

<em></em>

<em>x = 7 and x = -7</em>

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