2 years ago

How do I solve 4(x+3)=-6(4y-2)

Mathematics

1 answer:

True [87]2 years ago

4 0

<h2>Answer:</h2><h2>x=-6y</h2>

Step-by-step explanation:

Divide both sides by 4:

$\frac{4\left(x+3\right)}{4}=\frac{-6\left(4y-2\right)}{4}$

Simplify to give:

x+3 = -3(2y-1)

Subtract 3 from both sides:

x+3-3 = -3(2y-1)-3

Simplify to give your answer:

x=-6y

You might be interested in

Please look at the attached image. Really need Help!! Who ever find answer first will get brainily.

nadya68 [22]

Answer:

27°

Step-by-step explanation:

XWY and VWY are supplementary

∴ XWY + VWY = 180°

∴ XWY = 180° - VWY

XYW and ZYW are supplementary

∴ XYW + ZYW = 180°

∴ XYW = 180° - ZYW

ΔXWY is a right triangle at X

∴ XWY + XYW = 90°

∴ 180° - VWY + 180° - ZYW = 90°

∴ 180° - 6x + 180° - 4x = 90°

∴ 360° - 10x = 90°

∴ 10x = 270°

∴ x = 27°

7 0

2 years ago

Read 2 more answers

Find the product. (-2x^2)^3 ·3x

Dafna11 [192]

Answer:

-24 x^7

Step-by-step explanation:

(-2x^2)^3 ·3x

(-2x^2) (-2x^2) (-2x^2)*3x

-8 x^6 *3x

-24 x^7

3 0

2 years ago

The ratio of susan's money to isabella's money is 2:11. if susan $12, how much money does isbella have?

valentina_108 [34]

If Susan had 2$ and got to 12$ we need to find what multiplied by 2 = 12. So, 12/2=6
If 6x2=12 then 11x6=66
66$

7 0

2 years ago

PLZ HELP I ONLY 15 MINS I GIVE BRAIN 5 STAR AND THX

Andre45 [30]

Answer:

A I believe

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If triangle ABC defined by the coordinates A(1,1), B(9,1), C(1,9) is dilated by a scale factor of 1/2

alukav5142 [94]

Answer:

The transformed points of the triangle ABC are $A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right)$ , $B'(x,y) = \left(\frac{9}{2}, \frac{1}{2} \right)$ , $C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)$

Step-by-step explanation:

The new points after applying the scale factor are, respectively:

$A' (x,y) = \frac{1}{2}\cdot (1,1)$

$A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right)$

$B' (x,y) = \frac{1}{2}\cdot (9,1)$

$B'(x,y) = \left(\frac{9}{2}, \frac{1}{2} \right)$

$C'(x,y) = \frac{1}{2}\cdot (1,9)$

$C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)$

7 0

3 years ago