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myrzilka [38]
3 years ago
7

Gertrude started an experiment with 15 gummy bears. After 6 days, there were 1,523 gummy bears. Write an exponential function th

at could be used to model the number of gummy bears after x days if the number of gummy bears changes at the same rate. Round to the 4th decimal place (ten thousandth)
y=a*b^x
a=
b=​
Mathematics
1 answer:
Lunna [17]3 years ago
5 0

9514 1404 393

Answer:

  y = 15·2.1599^x

Step-by-step explanation:

We know that the number changed by the ratio 1523/15 = 101.5333... in 6 days, so the daily multiplier is the 6th root of this:

  b = 101.5333...^(1/6) = 2.1599 . . . rounded to 4 dp

Of course, the coefficient 'a' in the equation is the initial number, 15.

Your exponential equation is ...

  y = 15·2.1599^x

  a = 15

  b = 2.1599

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Fill in the blank to compare the two numbers below.
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Victor drew trapezoid PQRS on a coordinate plane p(7,4) q(10,4) r(13,-1) s(8,-1) what is length in units of side ps
olga nikolaevna [1]

Answer:

PS=\sqrt{26}units

Step-by-step explanation:

Given : PQRS is a trapezoid on a coordinate plane P(7,4) Q(10,4) R(13,-1) S(8,-1).

To find:: Length of the side PS

Solution : Using the distance formula, we can find the length of the side PS, therefore

PS=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2}

PS=\sqrt{(-1-4)^{2}+(8-7)^2 }

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5 0
3 years ago
Factorise (2t-7)²-(5t-4)² <br>with working pls​
sertanlavr [38]

Answer:

33+12t−21t^2

Step-by-step explanation:

(2t-7)²-(5t-4)²

Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (2t-7)².

4t^2−28t+49−(5t-4)²

Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (5t-4)².

4t^2−28t+49−(25t^2−40t+16)

To find the opposite of 25t^2

−40t+16, find the opposite of each term.

4t^2−28t+49−25t^2−40t+16

Combine 4t^2  and −25t^2  to get −21t^2.

−21t^2−28t+49+40t−16

Combine −28t and 40t to get 12t.

−21t^2+12t+49−16

Subtract 16 from 49 to get 33.

−21t^2+12t+33

Swap terms to the left side.

33+12t−21t^2

I hope this helped!

5 0
3 years ago
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