X-2y=-12
x+6y=20
we can cancel x's
multiply first equation by -1 and add to 2nd equation
-x+2y=12
<u>x+6y=20 +</u>
0x+8y=32
8y=32
divide both sides by 8
y=4
sub back
x-2y=-12
x-2(4)=-12
x-8=-12
add 12 both sides
x=-4
(x,y)
(-4,4)
Answer:
Step-by-step explanation:
16 divided by $3.50 = 4.5
<h2><em>Answer:</em></h2>
<u>Objects are placed after verbs. If the sentence has both a direct and an indirect object, the direct object comes first.</u>
<h3>
I believe it's <u>
C.</u></h3>
The slope of the line that is perpendicular to 6x + 2y = -32 is: 1/3.
<h3>What is the Slope of Perpendicular Lines?</h3>
The slope of two lines that are perpendicular to each other will always have a product that is equal to -1, which means that their slopes are negative reciprocals to each other.
Rewrite 6x + 2y = -32 in slope-intercept form:
2y = -6x - 32
2y/2 = -6x/2 - 32/2
y = -3x - 16
The slope is -3. Negative reciprocal of -3 is 1/3.
Therefore, the slope of the perpendicular line would be: 1/3.
Learn more about the slope of perpendicular lines on:
brainly.com/question/1362601
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