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3 years ago

Help me please! what goes in the box?

Mathematics

2 answers:

kvasek [131]3 years ago

7 0

Answer:

Answer:

-20/10

y=-20 x=10

Drupady [299]3 years ago

7 0

Answer:-36/-6=-6

Step-by-step explanation:

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Why did my question, "Describe the effects of the 2009 Samoa earthquake and tsunami" get deleted?

KIM [24]

Brainly deletes questions at random times.

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3 years ago

Read 2 more answers

Pat shows that 16 1/2= the square root of 16. What is one possible way pat could have shown this correctly?

kifflom [539]

<h3>Answer: Choice C</h3>

The base 16 is the same as 4*4.

From there, the rule $(a*b)^c = a^c*b^c$ is used to get $(4*4)^{1/2} = 4^{1/2}*4^{1/2}$

Afterward, the exponents are added getting 1/2+1/2 = 2/2 = 1. The rule is $a^b*a^c = a^{b+c}$ which only works if the bases are both the same.

6 0

3 years ago

9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

SSSSS [86.1K]

Answer:

Part 4) $r=84\ units$

Part 9) $sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) $sin(\theta)=-\frac{9\sqrt{202}}{202}$

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

$C=2\pi r$

using proportion

$\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}$

simplify

$\frac{r}{180^o}=\frac{56}{120^o}$

solve for r

$r=\frac{56}{120^o}(180^o)$

$r=84\ units$

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

$cos^2(\theta)+sin^2(\theta)=1$

we have

$cos(\theta)=-\frac{2}{3}$

substitute the given value

$(-\frac{2}{3})^2+sin^2(\theta)=1$

$\frac{4}{9}+sin^2(\theta)=1$

$sin^2(\theta)=1-\frac{4}{9}$

$sin^2(\theta)=\frac{5}{9}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{5}}{3}$

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

$sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?

see the attached figure to better understand the problem

In the right triangle ABC of the figure

$sin(\theta)=\frac{BC}{AC}$

Find the length side AC applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$AC^2=11^2+9^2$

$AC^2=202$

$AC=\sqrt{202}\ units$

$sin(\theta)=\frac{9}{\sqrt{202}}$

simplify

$sin(\theta)=\frac{9\sqrt{202}}{202}$

Remember that

The point (11,-9) lies in Quadrant IV

then

The value of sin(∅) is negative

therefore

$sin(\theta)=-\frac{9\sqrt{202}}{202}$

5 0

3 years ago

Benjamin is trying to find the height of a radio antenna on the roof of a local building.

xz_007 [3.2K]

The height of the antenna on the roof of the local building is approximately 8 meters.

The situation forms a right angle triangle.

<h3>Properties of a right angle triangle:</h3>

One of its angles is equals to 90 degrees
The sides of the triangles can be calculated using Pythagoras theorem.

Therefore, let's find the height of the building and the radio antenna from the eye point.

Using trigonometric ratios,

tan 40° = opposite / adjacent

tan 40° = x / 25

where

x = the height of the building and the radio antenna from the eye point.

x = 25 tan 40

x = 25 × 0.83909963117

x = 20.9774907794 meters

Let's find the height of the building from his eye point.

tan 28° = y / 25

where

y = height of the building from his eye point

y = 25 × tan 28°

y = 25 × 0.53170943166

y = 13.2927357915 meters

Height of the antenna = 20.9774907794 - 13.2927357915 = 7.68475498786

Height of the antenna ≈ 8 meters

learn more on elevation here: brainly.com/question/17582385?referrer=searchResults

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3 years ago

Write the expression in factored form x^2 + 12x + 36

Alex Ar [27]

(x + 6) (x + 6)

(x + 6)^2

6 0

3 years ago