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likoan [24]
3 years ago
11

The method of tree ring dating gave the following years A.D. for an archaeological excavation site. Assume that the population o

f x values has an approximately normal distribution.1229 1257 1313 1201 1268 1316 1275 1317 1275(a) Use a calculator with mean and standard deviation keys to find the sample mean year x and sample standard deviation s. (Round your answers to the nearest whole number.)x = A.D.s = yr(b) Find a 90% confidence interval for the mean of all tree ring dates from this archaeological site. (Round your answers to the nearest whole number.)lower limit A.D.upper limit A.D.

Mathematics
1 answer:
irga5000 [103]3 years ago
5 0

Answer:

1.The sample mean and standard deviation are 1272 and 40

2. The 90% confidence interval for the mean is between 1237 and 1306

Step-by-step explanation:

See attached picture for explanations.

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Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15. N an 1 4 2 −12 3 36 t
Rzqust [24]

By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is                    \sum_{n=4}^{15} 5(-2)^{n-1}$$  

<h3>What is sequence ?</h3>

Sequence is collection of  numbers with some pattern .

Given sequence

a_{1}=5\\\\a_{2}=-10\\\\\\a_{3}=20

We can see that

\frac{a_1}{a_2}=\frac{-10}{5}=-2\\

and

\frac{a_2}{a_3}=\frac{20}{-10}=-2\\

Hence we can say that given sequence is Geometric progression whose first term is 5 and common ratio is -2

Now n^{th}  term of this Geometric progression can be written as

T_{n}= 5\times(-2)^{n-1}

So summation of 15 terms can be written as

\sum_{n=4}^{15} T_{n}\\\\$\\$\sum_{n=4}^{15} 5(-2)^{n-1}$$

By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is                    \sum_{n=4}^{15} 5(-2)^{n-1}$$  

To learn more about Geometric progression visit : brainly.com/question/14320920

8 0
3 years ago
WHAT IS THE BENEFIT OF A "SPACE CUSHION" AROUND YOUR VEHICLE?
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A space cushion is a certain amount of distance you keep between u and the car in front of u that allows u to easily maneuver in any condition. The benefit would be : if another driver makes a mistake, ur space cushion gives u time to react.
4 0
3 years ago
Given circle Q with a measure of SR=120° and a radius of 9 feet, as shown below.
Pie

Answer:

18.85 feet

Step-by-step explanation:

Determine the arc length of SR

Arc length = θ/360 × 2πr

r = 9 feet

θ =120°

Arc length = 120/360 × 2 × π × 9

= 18.849555922 feet

Approximately = 18.85 feet

Therefore, the arc length of SR = 18.85 feet

6 0
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Click on the measure of angle x.<br> х<br> 38°<br> » 152<br> 1)) 142°<br> () 38°<br> )) 52°
GaryK [48]

Answer:

142°

Step-by-step explanation:

180^{\circ} - 38^{\circ} = 142^{\circ}

7 0
3 years ago
1 . Evaluate 3a - 12 divided by a for a =4 2. Evaluate 3x- 2y , if x= 5 and y =3
ziro4ka [17]
This is how I understood the question

Hope I helped!

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