What are the zeros of the polynomial x2+4x-12

1 answer:

3 0

Hi,
$x^2+4x-12=0\\

\Rightarrow\ x^2+6x-2x-12=)0\\
\Rightarrow\ x(x+6)-2(x+6)=0\\
\Rightarrow\ (x+6)(x-2)=0\\

\boxed{\Rightarrow\ x=-6\ or\ x=2}\\

$

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Step-by-step explanation:

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