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3 years ago

What are the zeros of the polynomial x2+4x-12

1 answer:

3 0

Hi,
$x^2+4x-12=0\\

\Rightarrow\ x^2+6x-2x-12=)0\\
\Rightarrow\ x(x+6)-2(x+6)=0\\
\Rightarrow\ (x+6)(x-2)=0\\

\boxed{\Rightarrow\ x=-6\ or\ x=2}\\

$

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Can someone please explain to me how to solve this?

lyudmila [28]

I hope this helps you

x= -2

h (-2)= 3. (-2)+1

h (-2)=-6+1

h (-2)= -5

4 0

3 years ago

When studying radioactive material, a nuclear engineer found that over 365 days, 1,000,000 radioactive atoms decayed to 973 co

HACTEHA [7]

Answer:

A. number of decayed atoms = 73.197

Step-by-step explanation:

In order to find the answer we need to use the radioactive decay equation:

$N(t)=N0*e^{kt}$ where:

N0=initial radioactive atoms

t=time

k=radioactive decay constant

In our case, when t=0 we have 1,000,000 atoms, so:

$1,000,000=N0*e^{k*0}$

$1,000,000=N0$

Now we need to find 'k'. Using the provied information that after 365 days we have 973,635 radioactive atoms, we have:

$973,635=1,000,000*e^{k*365}$

$ln(973,635/1,000,000)/365=k$

$-0.0000732=k$

A. atoms decayed in a day:

$N(t)=1,000,000*e^{-0.0000732t}$

$N(1)=1,000,000*e^{-0.0000732*1}$

$N(1)= 999,926.803$

Number of atoms decayed in a day = 1,000,000 - 999,926.803 = 73.197

B. Because 'k' represents the probability of decay, then the probability that on a given day 51 radioactive atoms decayed is k=0.0000732.

4 0

3 years ago

Find a ⋅ b. a = <5, 2>, b = <4, 5>

cestrela7 [59]

Answer:

Step-by-step explanation:

For a = <xa, ya> and b = <xb, yb>, the dot product is the sum of products ...

a·b = (xa)(xb) + (ya)(yb)

Substituting the given information, you have ...

a·b = 5·4 + 2·5 = 20 + 10

a·b = 30

_____

Some graphing calculators can do such math. There are also dot product calculators available on the Internet. If you have quite a few of these to calculate, you can put the appropriate formula into a spreadsheet.

6 0

3 years ago

Seven more than the quotient of a number and 4 is 9

erica [24]

you divide 8/4 and get 2. 2 plus 7 is 9

4 0

3 years ago

64 percent rounds to the nearest

Serggg [28]

Tenth have to make answer longer for this app sorry

5 0

3 years ago