2: 2/3; 3: 3/4; 4: 1/4; 5: 1/3; 6: 1/4; 7: 4/5; 8: 5/6-3/6=1/3
Answer:
2 1/3
1 4/3
2.333...
233.3...%
Step-by-step explanation:
Answer:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.
Step-by-step explanation:
Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:
Where
and
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
We can find a quantile in the normal standard distribution who accumulates 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64
Using this value we can set up the following equation:
And we have:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.
Answer:
distance is 5 units
Step-by-step explanation:
plug in values
Answer:
1 answer which would be -5+5 which =0
Step-by-step explanation: