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tatuchka [14]
4 years ago
15

Find the part what is 160% of 13.7

Mathematics
1 answer:
lidiya [134]4 years ago
5 0
13.7 is 100% I like to divide by 100 to get the 1%, then multiply by the percent i am trying to find, lets see if I'm right.
13.7/10 = .137
.137= 1/100
.137 x 160 = 21.92
Your answer is 21.92, 21.92 is 160%
Hope this helped!
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Does someone know how to solve this problem?
Naddika [18.5K]

Answer:

Acute scalene triangle.

Step-by-step explanation:

Acute scalene triangle.

Sides: a = 4   b = 7   c = 8

Area: T = 13.998

Perimeter: p = 19

Semiperimeter: s = 9.5

Angle ∠ A = α = 29.995° = 29°59'41″ = 0.524 rad

Angle ∠ B = β = 61.028° = 61°1'42″ = 1.065 rad

Angle ∠ C = γ = 88.977° = 88°58'37″ = 1.553 rad

Height: ha = 6.999

Height: hb = 3.999

Height: hc = 3.499

Median: ma = 7.246

Median: mb = 5.268

Median: mc = 4.062

Inradius: r = 1.473

Circumradius: R = 4.001

Vertex coordinates: A[8; 0] B[0; 0] C[1.938; 3.499]

Centroid: CG[3.313; 1.166]

Coordinates of the circumscribed circle: U[4; 0.071]

Coordinates of the inscribed circle: I[2.5; 1.473]

Exterior (or external, outer) angles of the triangle:

∠ A' = α' = 150.005° = 150°19″ = 0.524 rad

∠ B' = β' = 118.972° = 118°58'18″ = 1.065 rad

∠ C' = γ' = 91.023° = 91°1'23″ = 1.553 rad

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3 years ago
Marika solved the equation (6x + 15)2 + 24 = 0. Her work is below. 1. (6x + 15)2 = –24 2. StartRoot (6 + 15) squared EndRoot = S
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Answer:

There are no real solutions to this equation because the square root of a negative number is not real. So answer B

Step-by-step explanation:

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60 miles in 4 hours.
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2 is the base and (\sqrt[4][a^5 b^3]) is the exponent.

the 4 is called an index and it means to fi d the fourth root of the expression under the (\sqrt[][text]) symbol.\\a fourth root is a factor that was multiplied four times. ex: 2*2*2*2=16. the fourth root of 16 is two. \\when you do square roots, you take the number representing the factor out of the radical. anything else that is not a square root stays under. ex: \\([tex]\sqrt[9][text])\\([tex]\sqrt[3*3*3][text]) there is one set of two 3's so\\([tex]3\sqrt[3][text])\\with a fourth root, you look for groups of four. the symbol of that group is placed outside the radical. anything else stays in.\\ ([tex]\sqrt[4][a^5 b^3])

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(a\sqrt[4][a* b^3])

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here is the answer

Step-by-step explanation:

you may please search it

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