Take the derivative:
g’(x) = 12x^3 - 24x^2
Set equal to zero and solve:
0 = 12x^3 - 24x^2
0 = 12x^2 (x - 2)
x = 0 or x = 2
Plug back into original
g(0) = 3(0^4) - 8(0^3)
g(0) = 0 - 0
g(0) = 0
g(2) = 3(2^2) - 8(2^3)
g(2) = 3(4) - 8(8)
g(2) = 12 - 64
g(2) = -52
There is an absolute max at (0,0) or when x = 0
Answer:
C, A
Step-by-step explanation:
If you would like me to explain, I could but this would be difficult. Trust me.
Answer:
B=208.72
Step-by-step explanation:
June 22
July: 22+ 22x (1+10%) = 46.2
Auq: 46.2+ 22 (1+10%) x (1+10%)= 72.82
Sep: 72. 82+ 22 (1+10%)³= 102.102
Oct: 102.102 + 22 x(1+10%)⁴= 134.3122
Nov: 134.3122 + 22×(1+10%)⁵= 169.74342
Dec:169.74342 +22(1×10%)⁶ =208.717762
=208.72
The calulation of Compound interest )
Answer:
.
Step-by-step explanation:
