Y=-2/3x + 4 would be an equation that would fit
Answer:
Step-by-step explanation:Step 1: Use quadratic formula with a=1, b=-2, c=-2.
x=
−b±√b2−4ac
2a
x=
−(−2)±√(−2)2−4(1)(−2)
2(1)
x=
2±√12
2
x=1+√3 or x=1−√3
Answer:
x=1+√3 or x=1−√3
Answer:
Yes, there is sufficient evidence to support the claim that the mean cost is $1.
Step-by-step explanation:
Data Given:
The population standard deviation
= $0.2
The sample mean cost
= $0.93
The sample size n = 12
From above we can use the Z-test for testing the mean from the above given data.
To check whether the mean cost of newspaper is $1.00
:
= $1
:
$1
The test statistics Z = 
Z = 
Z = -1.212
The P-value = 2P (Z< - 1.212)
= 2 × 0.1128
= 0.2256
Since the value of P is more than the significance level; do not reject the 
Conclusion: We therefore conclude that there is sufficient evidence to support the claim that the mean cost is $1.
Answer:
Option A is correct
Step-by-step explanation:
The given equation is
h = -16t^2+6t+4
When the ball will hit the ground, height h = 0
Putting value of h = 0
0 = -16t^2+6t+4
Now solving to find the value of t
=> -16t^2+6t+4 = 0
Multiply with -1
16t^2-6t-4=0
Using quadratic formula to find value of t

a= 16, b= -6 and c= -4
Putting values,

Since time cannot be negative, so t = 0.721 or 0.72
So, Option A is correct