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2 years ago

Pls help me i will apprcieate it. Giving you brainlist ;)

Mathematics

1 answer:

andriy [413]2 years ago

7 0

The percent error of this problem is 5.85% error.

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Michael wrote a novel that sells for $20 dollars each. He received a bonus of $50,000 to sign the contract to write the book, an

Marat540 [252]

$50000 + (9%x(10000x$20)=
$50000 + (9%x$200000)=
$50000 + $18000=
$68000

4 0

3 years ago

What is thee answer?

Vanyuwa [196]

I think that it is B

4 0

3 years ago

Write an algebraic equation for the situation:

Diano4ka-milaya [45]

Answer:

ernie=X so Daniel = X-6

Step-by-step explanation:

5 0

3 years ago

Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''

Nonamiya [84]

Answer:

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

$D^2-1=0$

$(D-1)(D+1)=0$

D=1,-1

Then , the solution of given differential equation

$y=e^x,y=e^{-x}$

2. $7x^2y''+14xy'-14 y=0$

Y= $y=x^3$

$y=3x^2$

$y''=6x$

Substitute in the given differential equation

$42x^3+42x^3-14x^3\neq 0$

Hence, $x^3$ is not a solution of given differential equation

$e^x,e^{-x}$ are also not a solution of given differential equation.

y= $x^{-2}$

$y'=-2x^{-3}$

$y''=6x^{-4}$

Substitute the values in the differential equation

$7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}$

= $42x^{-2}-28x^{-2}-14x^{-2}=0$

Hence, $x^{-2}$ is a solution of given differential equation.

c. $7x^2y''-42y=0$

$y=x^3$

$y'=3x^2$

$y''=6x$

Substitute the values in the differential equation

$42x^3-42x^3=0$

Hence, $x^3$ is a solution of given differential equation.

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

6 0

3 years ago

Read 2 more answers

If the length of AB is 10 cm from the center and has a length of 12, find the approximate length from the center to CD.

Lynna [10]

Given–

AB = 12 Cm

CD = 14 Cm

PO = 10 Cm

AP = 1/2 × 12 = 6 Cm

Construction–

Draw NO such that it is the perpendicular bisector of CB.

Hence,

ND = 1/2 × 14 = 7 Cm

To Find,

Measure of NO

Solution,

Here, PO Perpendicular to AB

Hence, APO is a right-angled triangle–

AO² = PO² + AP²

Or, AO² = 10 ² + 6 ²

Or, AO² = 36 + 100

Or, AO = √136 Cm

Or, AO = 11.66 Cm

Also, AO = OD = 11.66 Cm

( Radius of the same circle )

Now, in triangle OND,

OD² = ON² + ND ²

Or, 11.66 ² = ON² + 7²

Or, 136 = ON² + 49

Or, ON ² = 136 – 49

Or, ON ² = 87

Or, ON ² = √87

Or, ON = 9.3 Cm

Therefore, the appropriate length from center to CD is 9.3 Cm.

4 0

3 years ago