Answer:
The proportion of temperatures that lie within the given limits are 10.24%
Step-by-step explanation:
Solution:-
- Let X be a random variable that denotes the average city temperatures in the month of August.
- The random variable X is normally distributed with parameters:
mean ( u ) = 21.25
standard deviation ( σ ) = 2
- Express the distribution of X:
X ~ Norm ( u , σ^2 )
X ~ Norm ( 21.25 , 2^2 )
- We are to evaluate the proportion of set of temperatures in the month of august that lies between 23.71 degrees Celsius and 26.17 degrees Celsius :
P ( 23.71 < X < 26.17 )
- We will standardize our limits i.e compute the Z-score values:
P ( (x1 - u) / σ < Z < (x2 - u) / σ )
P ( (23.71 - 21.25) / 2 < Z < (26.17 - 21.25) / 2 )
P ( 1.23 < Z < 2.46 ).
- Now use the standard normal distribution tables:
P ( 1.23 < Z < 2.46 ) = 0.1024
- The proportion of temperatures that lie within the given limits are 10.24%
Answer:
n<3
Step-by-step explanation:
2(8 +3n) < 34
16 + 6n < 34
6n < 34-16
6n < 18
n < 3
I hope this helps you
5x^2+30x+65=0
5 (x^2+6x+13)=0
x^2+6x+13=0
a=1 b=6 c=13
disctirminant=b^-4ac
disctirminant=6^2-4.1.13
disctirminant=36-52
disctirminant= -16
x1= -6+square root of -16/2.1
x1= -6+4i/2=2i-3
x2= -6- square root of -16/2.1
x2= -6-4i/2= -3-2i
Answer:
m = -11/7
Step-by-step explanation:
change equation into slope-intercept form:
7y = -11x + 2
y = -
x + 2/7
slope is the coefficient of the 'x' term
