
$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$
Step-by-step explanation:
If x=20 3x/5=12
Then if y=30 3y/5=18
It shows that A'B'C' smaller than ABC
I hope this helps you
O/360.2pi.19=4
O/180.3,14.19=4
O=12.0°
Answer: -30 and 30
Step-by-step explanation: