Assuming the order does not matter, you want the number of combinations of 9 things taken 5 at a time. The combinations can be shown as C(9,5), 9C5.
C(9, 5) =
9/5(9-5) =
9*8*7*6*5 / 5*4
The 5 terms cancel.
9*8*7*6 / 4*3*2 =
9*7*2 =
126
The above change is because 4*2 cancels the 8 in the numerator and 6/3 = 2
Therefore, the solution is 126.
Answer:
y=-4x^2+9x+9
Step-by-step explanation:
1st: we assume the equation will be in standard form (ax^2+bx+c)
2nd: since the graph passes through (0,9) then the y-intercept is @(0,9) or your c is 9.
3rd: since it passes through (2,11) then 11=4a+2b+c
4th: since it also passes through (3,0) then 0=9a+3b+c
* so we have c=9, 11= 4a+2b+c, and 0= 9a+3b+c*
So a=-4, b=9, c=9
plug in the numbers and you get y= 4x^2+9x+9
Hope this helps you. :3
WidthAnswer:
Step-by-step explanation: