2 years ago

(y-8)(y-8)(y-8) How do I multiply OR find the special product of this problem ?

Mathematics

1 answer:

photoshop1234 [79]2 years ago

5 0

Answer:

2x^3-23y^2+72-128

Step-by-step explanation:

its like when you just do two

do the first 2 first

(y-8)(y-8)

this is (y^2 -8y+y^2+16) simplify (2x^2-7y+16)

then add the other bracket

(2x^2-7y+16) (y-8)

2x^3-16x^2-7y^2+56y+16y-128 simplify

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