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3 years ago

(y-8)(y-8)(y-8) How do I multiply OR find the special product of this problem ?

Mathematics

1 answer:

photoshop1234 [79]3 years ago

5 0

Answer:

2x^3-23y^2+72-128

Step-by-step explanation:

its like when you just do two

do the first 2 first

(y-8)(y-8)

this is (y^2 -8y+y^2+16) simplify (2x^2-7y+16)

then add the other bracket

(2x^2-7y+16) (y-8)

2x^3-16x^2-7y^2+56y+16y-128 simplify

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A farmer needs to ship 71 pumpkins to a grocery store if each crates can hold 19 pumpkins how many crates Will the farmer need ?

Lesechka [4]

Answer:

The farmer will need 7 crates.

Step-by-step explanation:

It is given that there are 71 pumpkins in total.

And each crate holds 19 pumpkins.

Let the number of crates required be "n".

The total number of pumpkins can be calculated by multiplying number of pumpkins in each crate with total number of crates.

Thus, the equation is

$19(n) = 71$

$n = \frac{71}{19} = 7$

Thus, the farmer needs 7 crates to hold total of 71 pumpkins.

3 0

3 years ago

The fraction subtracted from 5/3 to get 1 is_____

siniylev [52]

Answer:

2/3

Step-by-step explanation:

I am not sure

7 0

3 years ago

Read 2 more answers

What is the purpose of finding the slope of a line

ikadub [295]

I think that it is so that you can find were it is on the graghing paper n

5 0

3 years ago

Let point C be between V and W on . Given that VW = 61, VC = z + 13, and CW = z + 8, solve for .

Rzqust [24]

VW=VC+CW
61=z+13+z+8
61=2z+21
2z=40
z=20

8 0

3 years ago

Drive to work in 45 min., bus to work takes 1 hr 15 min. If the average rate on the bus is 16 mph slower than his driving rate,

stich3 [128]

Answer:

30 miles

Step-by-step explanation:

Given: Drive to work in 45 min.

Bus would take to travel= 1 hr 15 min

Average rate on the bus is 16 mph slower than his driving rate.

Lets assume the average driving rate be "x" mph.

∴ Average rate of bus= $(x-16)\ mph$

Now converting unit of time taken to travel to work.

Remember; 1 hours= 60 minutes.

Time taken for drive to work= $\frac{45\ minutes}{60\ minutes} = 0.75\ hour$

Time taken in bus to work= 1 hour and 15 minutes= $60\ minutes+ 15\ minutes= 75\ minutes$

∴ Time taken in bus to work in hours= $\frac{75\ minutes}{60\ minutes}= 1.25\ hours$

Considering the distance remain constant to travel for work.

Next, forming an equation to find the value of x.

As we know, $distance= speed\times time$

⇒ $x\times 0.75= (x-16)\times 1.25$

Using distributive property of multiplication.

⇒ $0.75x= 1.25x-20$

Adding both side by 20

⇒ $0.75x+20= 1.25x$

Subtracting both side by 0.75x

⇒ $20= 0.5x$

Dividing both side by 0.5

⇒ $x= \frac{20}{0.5}$

∴ $x= 40\ mph$

Hence the average rate for drive to work is 40mph.

Now, subtitiuting the value of x to find the distance travelled to work.

Distance travelled= $40\times 0.75= 30\ miles$

Hence, distance travelled to work is 30 miles.

6 0

3 years ago