y < - 8 or y > 4
inequalities of the form | x | > a always have solutions of the form
x < - a or x > a
we have to solve
y + 2 < - 6 or y + 2 > 6
y + 2 < - 6 ( subtract 2 from both sides )
y < - 8
or
y + 2 > 6 ( subtract 2 from both sides )
y > 4
these can be combined using interval notation
y ∈ (- ∞, - 8 ) ∪ (4, ∞ )
As a check
substitute chosen values of x from each interval
y = - 10 : | - 10 + 2 | = | - 8 | = 8 > 6 this is true
y = 12 : | 12 + 2 | = | 14 | = 14 > 6 which is also true
Answer:
The way I was taught to do it is to change value into a total fraction, then multiple the numerators together, multiply the denominators together, and finally reduce as far as possible.
7/9 x 5 2/5 = 7/9 x 27/5 = 189/45 = 4 9/45 = 4 1/5
1 3/4 x 4 1/6 = 7/4 x 25/6 = 175/24 = 7 7/24
Step-by-step explanation:
12 is rounded to 10
22 is rounded to 20
20×10= 200
<span><span><span><span><span><span><span> I believe the answer is </span></span>x</span></span>=<span>−<span><span>1<span> or x = 0 or </span></span>x</span></span></span>=<span><span>1<span> or </span></span>x</span></span>=<span>−<span><span>3<span> </span></span></span></span></span>
He would use 3 cages for the canaries (6 in each) and 6 cages for the parakeets (7 in each)
