1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vladimir79 [104]
3 years ago
14

A student earned a grade 80% on a math test that had 20 problems. How many problems on this test did the student answer correctl

y?
Mathematics
1 answer:
prohojiy [21]3 years ago
8 0

Answer:

16

Step-by-step explanation:

5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,80

You might be interested in
The graph of y = |2x – 2| – 4 is shown.
Whitepunk [10]
Hi there!

The correct answer is the first option - an x intercept of the graph is (0,3). If you take a look at the graph, you'll see that one line crosses the x axis at (0,3). Meaning that, this is one x axis.

Hope this helps!! :)
8 0
3 years ago
Read 2 more answers
Solve image below:
ludmilkaskok [199]

Answer: x=\frac{6}{-3y+8}

Step-by-Step Explanation:

Let's solve for x.

\frac{x-2}{3y-5} =\frac{x}{3}

Step 1: Multiply both sides by 3y-5.

x-2=\frac{3xy-5x}{3}

Step 2: Multiply both sides by 3.

3x-6=3xy-5x

Step 3: Add -3xy to both sides.

3x-6+-3xy=3xy-5x+-3xy

-3xy+3x-6=-5x

Step 4: Add 5x to both sides.

-3xy+3x-6+5x=-5x+5x

-3xy+8x-6=0

Step 5: Add 6 to both sides.

-3xy+8x-6+6=0+6

-3xy+8x=6

Step 6: Factor out variable x.

x(-3y+8)=6

Step 7: Divide both sides by -3y+8.

\frac{x(-3y+8)}{-3y+8}=\frac{6}{y-3y+8}

x=\frac{6}{-3y+8}

Answer:

x=\frac{6}{-3y+8}

4 0
2 years ago
2/3 ÷ 3/4 simplify the fraction expression
adelina 88 [10]

0.8 is the simplified answer I believe.

3 0
3 years ago
Read 2 more answers
2ab + a^3 +5a^2b^2 - 2b^3<br> Need help i have to write this in standard form
german
2ab + a^3 + 5a^2b^2 - 2b^3
= a^3 - 2b^3 + 2ab + 5a^2b^2 (this is the expression in standard form)
4 0
3 years ago
Read 2 more answers
Which statement describes the inverse of m(x) = x^2 – 17x?
DochEvi [55]

Given:

The function is

m(x)=x^2-17x

To find:

The inverse of the given function.

Solution:

We have,

m(x)=x^2-17x

Substitute m(x)=y.

y=x^2-17x

Interchange x and y.

x=y^2-17y

Add square of half of coefficient of y , i.e., \left(\dfrac{-17}{2}\right)^2 on both sides,

x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2        [\because (a-b)^2=a^2-2ab+b^2]

Taking square root on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}

Add \dfrac{17}{2} on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y

Substitute y=m^{-1}(x).

m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}

We know that, negative term inside the root is not real number. So,

x+\left(\dfrac{17}{2}\right)^2\geq 0

x\geq -\left(\dfrac{17}{2}\right)^2

Therefore, the restricted domain is x\geq -\left(\dfrac{17}{2}\right)^2 and the inverse function is m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}.

Hence, option D is correct.

Note: In all the options square of \dfrac{17}{2} is missing in restricted domain.

7 0
3 years ago
Other questions:
  • Convert 0.001 to a power of ten
    5·1 answer
  • Graph each pair of parametric equations.<br><br> x = 3 sin3t<br> y = 3 cos3t
    10·1 answer
  • How do you solve 7/10-3/5
    9·2 answers
  • Write an expression that is equivalent to<br> 4 (b+2) - 3b
    14·2 answers
  • What is the greatest common factor of 12 and 26
    15·2 answers
  • 6) En El Salvador el presupuesto de gastos para el año 2020 fue de 500 millones dos ciento cincuenta mil dólares, de los que le
    15·1 answer
  • Which of these describes two thirds?​
    12·1 answer
  • Please help me if you can thank you.
    13·1 answer
  • How do you find the inverse f-1(x) given f(x)=x^3+7?
    11·1 answer
  • Match each of the English phrases with the correct math translation.
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!