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Vladimir79 [104]

3 years ago

14

A student earned a grade 80% on a math test that had 20 problems. How many problems on this test did the student answer correctl

y?

1 answer:

prohojiy [21]3 years ago

8 0

Answer:

16

Step-by-step explanation:

5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,80

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The graph of y = |2x – 2| – 4 is shown.

Whitepunk [10]

Hi there!

The correct answer is the first option - an x intercept of the graph is (0,3). If you take a look at the graph, you'll see that one line crosses the x axis at (0,3). Meaning that, this is one x axis.

Hope this helps!! :)

8 0

3 years ago

Read 2 more answers

Solve image below:

ludmilkaskok [199]

Answer: $x=\frac{6}{-3y+8}$

Step-by-Step Explanation:

Let's solve for $x$ .

$\frac{x-2}{3y-5} =\frac{x}{3}$

Step 1: Multiply both sides by $3y-5$ .

$x-2=\frac{3xy-5x}{3}$

Step 2: Multiply both sides by $3$ .

$3x-6=3xy-5x$

Step 3: Add $-3xy$ to both sides.

$3x-6+-3xy=3xy-5x+-3xy$

$-3xy+3x-6=-5x$

Step 4: Add $5x$ to both sides.

$-3xy+3x-6+5x=-5x+5x$

$-3xy+8x-6=0$

Step 5: Add $6$ to both sides.

$-3xy+8x-6+6=0+6$

$-3xy+8x=6$

Step 6: Factor out variable $x$ .

$x(-3y+8)=6$

Step 7: Divide both sides by $-3y+8$ .

$\frac{x(-3y+8)}{-3y+8}=\frac{6}{y-3y+8}$

$x=\frac{6}{-3y+8}$

Answer:

$x=\frac{6}{-3y+8}$

4 0

2 years ago

2/3 ÷ 3/4 simplify the fraction expression

adelina 88 [10]

0.8 is the simplified answer I believe.

3 0

3 years ago

Read 2 more answers

2ab + a^3 +5a^2b^2 - 2b^3<br> Need help i have to write this in standard form

german

2ab + a^3 + 5a^2b^2 - 2b^3
= a^3 - 2b^3 + 2ab + 5a^2b^2 (this is the expression in standard form)

4 0

3 years ago

Read 2 more answers

Which statement describes the inverse of m(x) = x^2 – 17x?

DochEvi [55]

Given:

The function is

$m(x)=x^2-17x$

To find:

The inverse of the given function.

Solution:

We have,

$m(x)=x^2-17x$

Substitute m(x)=y.

$y=x^2-17x$

Interchange x and y.

$x=y^2-17y$

Add square of half of coefficient of y , i.e., $\left(\dfrac{-17}{2}\right)^2$ on both sides,

$x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

Taking square root on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}$

Add $\dfrac{17}{2}$ on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y$

Substitute $y=m^{-1}(x)$ .

$m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$

We know that, negative term inside the root is not real number. So,

$x+\left(\dfrac{17}{2}\right)^2\geq 0$

$x\geq -\left(\dfrac{17}{2}\right)^2$

Therefore, the restricted domain is $x\geq -\left(\dfrac{17}{2}\right)^2$ and the inverse function is $m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$ .

Hence, option D is correct.

Note: In all the options square of $\dfrac{17}{2}$ is missing in restricted domain.

7 0

3 years ago