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MAXImum [283]
2 years ago
14

Using only numbers in the following list,

Mathematics
2 answers:
charle [14.2K]2 years ago
6 0

Answer:

wgfregrt

Step-by-step explanation:

tryryrtrtytrytry

grandymaker [24]2 years ago
4 0

Answer:

A) 48,32

B) 89, 46

C) 48

Step-by-step explanation:

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The equation is =360
frosja888 [35]

Given:

Angles of the quadrilateral are 100°, 120°, 100° and x°.

To find:

The value of x.

Solution:

The sum of the angle measures of the quadrilateral is 360°.

\Rightarrow 100^\circ+120^\circ+100^\circ+x^\circ=360^\circ

\Rightarrow 320^\circ+x^\circ=360^\circ

Subtract 320° from both sides.

\Rightarrow 320^\circ+x^\circ-320^\circ=360^\circ-320^\circ

\Rightarrow x^\circ=40^\circ

The equation of 320 + x = 360.

The value of x is 40.

3 0
3 years ago
PLEASEEE HELPPP ILL GIVE BRAINLY ANSWEAR ALL OF THEM!!!!!
Svetradugi [14.3K]
Use Photomath that will help you on those type of problems.

5 0
3 years ago
Read 2 more answers
Claire had 4 1/6 feet of string. She used some string to hang out decorations. Now she has 1 5/6 feet of string left. How much s
vodka [1.7K]

Answer:

Length of string used by Claire = 7 / 3 feet

Step-by-step explanation:

Given:

Length of string Claire in starts = 4\frac{1}{6} feet

Length of string Claire in end = 1\frac{5}{6} feet

Find:

Length of string used by Claire

Computation:

Length of string Claire in starts = 4\frac{1}{6} feet = 25 / 6 feet

Length of string Claire in end = 1\frac{5}{6} feet = 11 / 6 feet

Length of string used by Claire = Length of string Claire in starts - Length of string Claire in end

Length of string used by Claire = [25 / 6] - [11 / 6]

BY taking LCM

Length of string used by Claire = [25 - 11] / 6

Length of string used by Claire = 14 / 6

Length of string used by Claire = 7 / 3 feet

8 0
2 years ago
Which equation is satisfied by all of the plotted points?
Brums [2.3K]
The equation that is satisfied by all of the plotted points would be F. 3x because the y-intercept is at 0 so there wouldn't be one and the graph has a ratio of 3/1 so for every 3 numbers the line moves up it moves 1 space to the right, also indicating that it is positive.
3 0
3 years ago
A flea weighs 8 decigrams, and an ant weighs 3 milligrams. How much more does a flea weigh than an ant?
dusya [7]
In this question weight of a flea and an ant is given, but their units are different. So comparing and finding out the weight of flea and ant would be difficult. First thing that needs to be done is to bring the units of both the flea and the ant under same unit.
Weight of flea = 8 decigrams
Weight of ant = 3 milligrams.
Now let us convert the weight of the flea from decigrams to milligrams.
We already know that
1 decigram = 100 milligram
Then
8 decigrams = 100 * 8 milligrams
                     = 800 milligrams
Then
The weight by which the flea is greater than the ant = (800 - 3) milligrams
                                                                                   = 797 milligrams.
So the flea weighs 797 milligrams more than the ant.

5 0
3 years ago
Read 2 more answers
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