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3 years ago

Pls help......pic included...with work pls don't do solving equations containing decimals

Mathematics

2 answers:

kipiarov [429]3 years ago

8 0

Answer:

22. 3x/3=30/3 x=10

23. K-25=50

+25

K=75

24. Y+16=-8

-16

Y=-24

19. W-4=-6

W=-2

20. X+5= -5

-5

X=-10

21. -6a/-6=60/-6

A= -10

22. (-4/1)h/-4=12(-4/1)

H=12x -4

H= -48

Step-by-step explanation:

Mice21 [21]3 years ago

6 0

Answer:

22. x = 10

23. k = 75

24. y = -24

Solve:

19. w = -2

20. x = -10

21. a = -10

22. n = -48

Step-by-step explanation:

Too many questions for explanation sorry.

Hope this helps! Have a nice day!

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4:3 19:11 equivalent ratios?

maria [59]

Answer:

Step-by-step explanation:

We can tell if these ratios are equivalent by dividing the numerators and denominators. If we end up with the same result, these ratios are equivalent.

 $\frac{4}{3}$   $\frac{19}{11}$ 

 $19 \div 4 = 4.75\\\\11\div 3 = 3.\overline{66}$ 

These two numbers are not equivalent, so these ratios aren't equivalent to each other

Hope this helped!

6 0

3 years ago

Which expression is a cube root of -1+i√3?

Tpy6a [65]

Answer:

The correct option is C.

Step-by-step explanation:

Root Of Complex Numbers

If a complex number is expressed in polar form as

$Z=(r,\theta)$

Then the cubic roots of Z are

$\displaystyle Z_1=\left(\sqrt[3]{r},\frac{\theta}{3}\right)$

$\displaystyle Z_2=\left(\sqrt[3]{r},\frac{\theta}{3}+120^o\right)$

$\displaystyle Z_3=\left(\sqrt[3]{r},\frac{\theta}{3}+240^o\right)$

We are given the complex number in rectangular components

$Z=-1+i\sqrt{3}$

Converting to polar form

$r=\sqrt{(-1)^2+(\sqrt{3})^2}=2$

$\displaystyle tan\theta=\frac{\sqrt{3}}{-1}=-\sqrt{3}$

It's located in the second quadrant, so

$\theta=120^o$

The number if polar form is

$Z=(2,120^o)$

Its cubic roots are

$\displaystyle Z_1=\left(\sqrt[3]{2},\frac{120^o}{3}\right)=\left(\sqrt[3]{2},40^o\right)$

$\displaystyle Z_2=\left(\sqrt[3]{2},40^o+120^o\right)=\left(\sqrt[3]{2},160^o\right)$

$\displaystyle Z_3=\left(\sqrt[3]{2},40^o+240^o\right)=\left(\sqrt[3]{2},280^o\right)$

Converting the first solution to rectangular coordinates

$z_1=\sqrt[3]{2}(\ cos40^o+i\ sin40^o)$

The correct option is C.

8 0

4 years ago

If possible, complete the equation below that uses the law of cosines to find the remaining side of the triangle.

romanna [79]

Answer:

Option C.

a = 20.3

Step-by-step explanation:

Given:

m<A = 32°

a = ??

b = 16

c = 32

Required:

Find a

SOLUTION;

To find the missing side, a, of the triangle, apply the Law of Cosines, $a^2 = b^2 + c^2 - 2bcCosA$

Plug in the values into the equation:

$a^2 = 16^2 + 32^2 - 2(16)(32)Cos32$

$a^2 = 1,280 - 1,024*Cos32$

$a^2 = 1,280 - 868.40125$

$a^2 = 411.59875$

$a = \sqrt{411.59875}$

$a = 20.3$ (nearest tenth)

4 0

3 years ago

Represent the following sentence as an algebraic expression, where "a number" is the letter x.

matrenka [14]

By the difference of "5 and a number", I assume you mean that number minus 5. In that case, the expression is 8 times (x-5).

If by "the difference of 5 and a number" you mean 5 minus that number, then the expression is 8 times (5-x).

7 0

4 years ago

Josh is mixing together concrete to build a brick wall. He's made 6 gallons of concrete with a mixture of 50% water. The instruc

katrin2010 [14]

Answer:

15%.,..........,..............,.......,..............,...........

3 0

4 years ago