All categories

3 years ago

Four tenths plus four ninths.

Mathematics

1 answer:

stich3 [128]3 years ago

6 0

Answer:

Step-by-step explanation:

You might be interested in

What solid shape does the two nets make?

Paha777 [63]

Answer:

1. Rectangular Prism

2. Triangular prism

Step-by-step explanation:

7 0

4 years ago

An employee is marking up new merchandise by 35%. the price they paid for an item is $120. what price will the employee place on

kolezko [41]

The answer would be D: $162 because $120 x 35% or (0.35) = $42 so $120 + $42 gives you $162

4 0

4 years ago

Read 2 more answers

1/(x-1)x+1/x(x+1)+...+1/(x+9)(x+10)=11/12

nata0808 [166]

Notice that

$\dfrac1{(x-1)x} = \dfrac1{x-1} - \dfrac1x \\\\ \dfrac1{x(x+1)} = \dfrac1x - \dfrac1{x+1} \\\\ \vdots \\\\ \dfrac1{(x+9)(x+10)} = \dfrac1{x+9} - \dfrac1{x+10}$

That is, the n-th term (where n = -1, 0, 1, …, 9) in the sum on the left side has a partial fraction decomposition of

$\dfrac{1}{(x+n)(x+n+1)} = \dfrac1{x+n} - \dfrac1{x+n+1}$

and in the sum, some adjacent terms will cancel and leave you with

$\dfrac1{(x-1)x} + \dfrac1{x(x+1)} + \cdots + \dfrac1{(x+9)(x+10)} = \dfrac1{x-1} - \dfrac1{x+10} = \dfrac{11}{12}$

Now solve for x, bearing in mind that we cannot have x = 0, -1, -2, …, -10 :

$\dfrac1{x-1} - \dfrac1{x+10} = \dfrac{11}{12}$

Combine the fractions on the left side:

$\dfrac{(x+10)-(x-1)}{(x-1)(x+10)} = \dfrac{11}{(x-1)(x+10)} = \dfrac{11}{12}$

Then we must have

$(x-1)(x+10) = x^2 + 9x - 10 = 12 \implies x^2+9x-22 = (x+11)(x-2) = 0$

so that either x = 2 or x = -11.

4 0

3 years ago

Given the following data for resting heartrate among college students, what is the IQR? 57, 59, 60, 62, 62, 63, 64, 68, 70, 70,

aev [14]

Answer:

Step-by-step explanation:

The inter-quartile range (IQR) is the difference between the third and first quartile. The data gathered is:

57, 59, 60, 62, 62, 63, 64, 68, 70, 70, 71, 71, 73, 79, 87, 89, 90

The data set has 17 values, the first quartile is the average between the 4th and 5th values, while the third quartile is the average between the 13th and 14th values:

$Q_1 = \frac{62+62}{2}=62\\Q_3 = \frac{73+79}{2}=76$

The IQR is:

$IQR = Q_3 - Q_1 = 76 -62\\IQR = 14$

8 0

3 years ago

Algebra hcf 10xyz and 15y²z²

boyakko [2]

Answer:

5yz

Step-by-step explanation:

1st expression=10xyz

=5*2*x*y*z

2nd expression=15(y)2 (z)2

=5*3*y*y*z*z

therefore H.C.F=5yz

underlines are taking common.

3 0

3 years ago