Algebra hcf10xyz and 15y²z²
1 answer:
Answer:
5yz
Step-by-step explanation:
1st expression=10xyz
=<u>5</u>*2*x*<u>y</u>*<u>z</u>
2nd expression=15(y)2 (z)2
=<u>5</u>*3*<u>y</u>*y*z*<u>z</u>
therefore H.C.F=5yz
underlines are taking common.
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