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steposvetlana [31]
4 years ago
5

15% of the apples in a crate are rotten. There are 12 rotten apples in the crate.

Mathematics
2 answers:
Svetradugi [14.3K]4 years ago
8 0
There are a total of 80 apples in the crate. 

Hope this helps!:)
viktelen [127]4 years ago
7 0
There are 80 apples in the crate.
Hope this helps! :D
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Andre45 [30]

Answer:

Take a better picture so I can see better

Step-by-step explanation:

4 0
4 years ago
8xy+4xy^2<br> what is the result ?
Molodets [167]

Answer:

4xy(2+y)

Step-by-step explanation:

Factor  4 x y  out of  8 x y .

4xy(2)+4xy^2

Factor 4xy out of 4xy^2

4xy(2) + 4xy(y)

Factor  4 x y  out of  4 x y ( 2 )  +  4 x y ( y ) .

4xy(2+y)

hope this helps :)

7 0
3 years ago
What is the sum of 12 – 5i and –3 + 4i?<br> –16 + 63i <br>9 – i <br>9 – 9i <br>15 – 9i
Svetach [21]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{9 - i}}}}}

Step-by-step explanation:

\sf{12 - 5i + ( - 3 + 4i)}

When there is a ( + ) in front of an expression in parentheses, there is no need to change the sign of each term. That means, the expression remains the same. Just remove the parentheses

\longrightarrow{ \sf{12 - 5i - 3 + 4i}}

Collect like terms

\longrightarrow{ \sf{ 12 - 3 - 5i + 4i}}

Subtract 3 from 12

\longrightarrow{ \sf{9 - 5i + 4i}}

Collect like terms

\longrightarrow{ \sf{9 - i}}

Hope I helped!

Best regards! :D

3 0
3 years ago
Read 2 more answers
It is known that IQ scores form a normal distribution with a mean of 100 and a standard deviation of 15. If a researcher obtains
sdas [7]

Answer:

X \sim N(100,15)  

Where \mu=100 and \sigma=15

We select a sample of n=16 and we are interested on the distribution of \bar X, since the distribution for X is normal then we can conclude that the distribution for \bar X is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Because by definition:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

E(\bar X) = \mu

Var(\bar X) = \frac{\sigma^2}{n}

And for this case we have this:

\mu_{\bar X}= \mu = 100

\sigma_{\bar X} = \frac{15}{\sqrt{16}}= 3.75

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

X \sim N(100,15)  

Where \mu=100 and \sigma=15

We select a sample of n=16 and we are interested on the distribution of \bar X, since the distribution for X is normal then we can conclude that the distribution for \bar X is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Because by definition:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

E(\bar X) = \mu

Var(\bar X) = \frac{\sigma^2}{n}

And for this case we have this:

\mu_{\bar X}= \mu = 100

\sigma_{\bar X} = \frac{15}{\sqrt{16}}= 3.75

6 0
3 years ago
Find x<br> X=<br> Can someone pls help
garik1379 [7]

Answer:

Step-by-step explanation:

6

4 0
3 years ago
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