Question

Find sin18 /cos72please help I am writing exam​

Answer 1

Answer:

sin 18 = cos ( 90 - 72 ) = sin 18

so,

sin 18 / cos 72 = sin 18 / sin 18 = 1

Step-by-step explanation:

so required answer is 1

Answer 2

Answer:

sin18/cos72= sin(18) sec(72)

Step-by-step explanation:

rewrite it as a product: sin(18)/1 * 1/cos(72)

Divide sin(18) by 1 and rewrite 1/cos(72) as sec(72): sin (18) sec (72)