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Alex787 [66]
2 years ago
14

What is the relation between distance travelled by a train and its speed, when time is constant?

Mathematics
1 answer:
Oliga [24]2 years ago
4 0

Answer:

direct relation between distance travelled by a train and its speed, when time is constant.

Step-by-step explanation:

We know that the speed of an object is the total distance covered divided by total time taken. Mathematically, it is given by :

v=\dfrac{d}{t}

Where

d is distance

t is time taken

It can be seen that relation between the distance and the speed is direction. Hence the correct option is (a) "direct".

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Plsssssss helppp ;w;w;
drek231 [11]

<u>Answer:</u>

Given below.

<u>Explanation:</u>

Coordinates given: W( -4, -3 ) , X( 1 , -2 ), Y(2, -7 ) , Z( -3, -8)

To find the distance we will use the formula: distance=√((x2-x1)²+(y2-y1)²)

WX = √((1--4)²+(-2--3)²)

      = √26

YZ = √((-3-2)²+(-8--7)²)

     = √26

XY = √((2-1)²+(-7--2)²)

     = √26

WZ = √(-3--4)²+(-8--3)²

      = √26

WY =  √(2--4)²+(-7--3)²

     = 2√13

XZ = √(-3-1)²+(-8--2)²

     = 2√13

7 0
2 years ago
Read 2 more answers
Find the real or imaginary solutions of each equation by factoring
anyanavicka [17]
Sum of  2 perfect cubes
a³+b³=(a+b)(x²-xy+y²)
so

x³+4³=(x+4)(x²-4x+16)
set each to zero
x+4=0
x=-4

the other one can't be solveed using conventional means
use quadratic formula
for
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}
for x²-4x+16=0
x=\frac{-(-4)+/- \sqrt{(-4)^2-4(1)(16)} }{2(1)}
x=\frac{4+/- \sqrt{16-64} }{2}
x=\frac{4+/- \sqrt{-48} }{2}
x=\frac{4+/- (\sqrt{-1})(\sqrt{48}) }{2}
x=\frac{4+/- (i)(4\sqrt{3}) }{2}
x=2+/- 2i\sqrt{3}


the roots are
x=-4 and 2+2i√3 and 2-2i√3
8 0
3 years ago
Helpppppppppppppp pleaseee! Geometry
anzhelika [568]
Ts A. Congurent only denotes something being of the same shape and size, so if one wouldn't right and the other wasn't they wouldn't be identical, which is what its about. 
7 0
3 years ago
Read 2 more answers
HELPPP PLEASEEEE
Kryger [21]

Answer:

I think glide reflection

Step-by-step explanation:

a certain video on yt had explained the examples of similar look alike this picture

3 0
2 years ago
Seema covered 3 4/13(three four by thirteen)km by bus,2 5/13(Two five by thirteen)km by metro and 1 2/13(One two by thirteen)km
Ad libitum [116K]

Answer: 89/13 km

Step-by-step explanation:

3 4/13 + 2 5/13 + 1 2/13

= 43/13 + 31/13 + 15/13

= 89/13 km

6 0
3 years ago
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