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antoniya [11.8K]
3 years ago
14

Need help!!! Worth 13 points!

Mathematics
1 answer:
alisha [4.7K]3 years ago
3 0
All you have to do is plug in the given values for a and b.

0.9a - 1.5b = ?

a = 15
b = 3

0.9 (15) - 1.5 (3)

= 13.5 - 4.5

= 9

Note:

•Integers are whole numbers.
For ex: 1, 2, 3, 4...

•Decimals have a period in between 2 numbers
For ex: 0.1, 0.2, 0.3

Sometimes when it’s concerning significant digits then decimals could also be
1.0, 2.0, 3.0 ... I wouldn’t worry about this right now until you get into higher years



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What is the area of this figure???
pshichka [43]

Answer:

24 mm squared

Step-by-step explanation:

3 x 4 x 1/2 = area of the triangle

4 x 3 = area of the rectangular top left

1 x 6 = area of the bottom rectangle

3 x 4 = 12 x 1/2 = 6

4 x 3 = 12

6 x 1 = 6

6 + 12 + 6 =24

8 0
3 years ago
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4/ PLEASE HELP ME ON THIS. ASAP
rewona [7]

Answer: a,b,d,e are all right beacuse they all relate to the question

Step-by-step explanation:

c how ever is no shown on the graph and is therefor wrong

4 0
3 years ago
What is 4/9 • t when t=1/3
Reptile [31]
\frac{4}{9}* \frac{1}{3}= \frac{4}{27}
8 0
3 years ago
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20 points!!! first answer gets brainliast. Don't need too much explanation thank you!​
KengaRu [80]

Answer:

The answer to your question is below

Step-by-step explanation:

2. \sqrt{-128}                Just find the prime factors of 128 and simplify

   \sqrt{-2^{7}} = \sqrt{-2^{6} 2} = 2^{3}i \sqrt{2}

   8i\sqrt{2}

3.- \sqrt{-9} + \sqrt{-16}     Get the square roots and simplify

     3i + 4i

     7i

4.- None of the choices is equal to one, because the exponents are pair.

5.- 1/3x² + 10 = 7

    1/3x² = 7 - 10

    1/3x² = -3

         x² = -3(3)

         x² = -9

         x = ±3i

8 0
3 years ago
If W(-10, 4), X(-3, -1), and Y(-5, 11) classify ΔWXY by its sides. Show all work to justify your answer.
solniwko [45]

Given:

The vertices of ΔWXY are W(-10, 4), X(-3, -1), and Y(-5, 11).

To find:

Which type of triangle is ΔWXY by its sides.

Solution:

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

WX=\sqrt{(-3-(-10))^2+(-1-4)^2}

WX=\sqrt{(-3+10)^2+(-5)^2}

WX=\sqrt{(7)^2+(-5)^2}

WX=\sqrt49+25}

WX=\sqrt{74}

Similarly,

XY=\sqrt{\left(-5-\left(-3\right)\right)^2+\left(11-\left(-1\right)\right)^2}=2\sqrt{37}

WY=\sqrt{\left(-5-\left(-10\right)\right)^2+\left(11-4\right)^2}=\sqrt{74}

Now,

WX=WY

So, triangle is an isosceles triangles.

and,

WX^2+WY^2=(\sqrt{74})^2+(\sqrt{74})^2

WX^2+WY^2=74+74

WX^2+WY^2=148

WX^2+WY^2=(2\sqrt{37})^2

WX^2+WY^2=WY^2

So, triangle is right angled triangle.

Therefore, the ΔWXY is an isosceles right angle triangle.

3 0
3 years ago
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