20 points!!! first answer gets brainliast. Don't need too much explanation thank you!
1 answer:
Answer:
The answer to your question is below
Step-by-step explanation:
2. Just find the prime factors of 128 and simplify
3.- Get the square roots and simplify
3i + 4i
7i
4.- None of the choices is equal to one, because the exponents are pair.
5.- 1/3x² + 10 = 7
1/3x² = 7 - 10
1/3x² = -3
x² = -3(3)
x² = -9
x = ±3i
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Answer:
Option C.
Step-by-step explanation:
we know that
The surface area of the triangular prism using the net is equal to the area of two triangles plus the area of three rectangles
so
All we need is to put this form in the vertex form f(x) = (ax+b)^2 + c
So we have <span>f (x)= 3x^2+12x+11 ....
Let's complete the square (if you aware of it)
</span><span>
f(x)= 3x^2+12x+11 = 3(x^2+4x)+11 = 3(x^2+4x+4-4)+11
=</span><span> 3([x^2+4x+4]-4)+11 = 3[(x+2)^2-4]+11 =3</span><span>(x+2)^2 - 12 +11 = 3</span><span><span>(x+2)^2 -1
so our form would be:
Here is a parabola with vertex of (-2,-1) and with positive </span> slope (concave up)
</span>
So we have <span>f (x)= 3x^2+12x+11 ....
Let's complete the square (if you aware of it)
</span><span>
f(x)= 3x^2+12x+11 = 3(x^2+4x)+11 = 3(x^2+4x+4-4)+11
=</span><span> 3([x^2+4x+4]-4)+11 = 3[(x+2)^2-4]+11 =3</span><span>(x+2)^2 - 12 +11 = 3</span><span><span>(x+2)^2 -1
so our form would be:
Here is a parabola with vertex of (-2,-1) and with positive </span> slope (concave up)
</span>
I hope that helps!