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maksim [4K]
3 years ago
9

(-4).(-4).(-4). y. y

Mathematics
1 answer:
Andre45 [30]3 years ago
7 0

Answer:-64y^2

Step-by-step explanation:

-4x-4=16

16x-4=-64

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2. (01.02 MC)<br> Find the value of the expression 4a4 – 2b2 + 40 when a = 2 and b = 7. (5 points)
Sergio039 [100]

Answer:

4x2x4 - 2×7×2 + 40

64 - 28 + 40=76

6 0
2 years ago
michael has a very large soup pot shape like a cylinder that has height of 15 inches and a radius of 6 inches
belka [17]

Answer:

  • 1695.6 in³

Step-by-step explanation:

<em>Cylinder volume formula: V= πr²h</em>

<u>Given</u>

  • h = 15 in
  • r = 6 in

<u>Volume of soup pod</u>

  • V = 3.14*6²*15 = 1695.6 in³
8 0
3 years ago
PLEASE HELP!!! ILL GIVE BRAINLIEST<br><br><br> what is the function rule is slope
sergey [27]

Answer:

here!

Step-by-step explanation:

How to write a function rule using the concept of slope. Let us do this for example #3. The goal is use the equation y = mx + b. y = 4x + b. Use (1,6) to find b. 6 = 4 + b.

8 0
2 years ago
TOP OF THE MORNIN TO THE PEOPLE THAT CAN ANSWER THIS!!!!
Dvinal [7]
<span>surface area=4π<span>r2</span>=2700 c<span>m2</span></span>
<span><span>r2</span>=<span>2700<span>4π</span></span>=<span>2700<span>4×3</span></span>=225</span>
<span>r=<span>225<span>−−−</span>√</span>=15</span>
<span><span>volume=<span>43</span>π<span>r3</span>=<span>43</span>×3×<span>153</span>=13500 c<span>m3</span></span></span>
7 0
3 years ago
Solve the Differential equation (x^2 + y^2) dx + (x^2 - xy) dy = 0
natita [175]

Answer:

\frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C

Step-by-step explanation:

Given differential equation,

(x^2 + y^2) dx + (x^2 - xy) dy = 0

\implies \frac{dy}{dx}=-\frac{x^2 + y^2}{x^2 - xy}----(1)

Let y = vx

Differentiating with respect to x,

\frac{dy}{dx}=v+x\frac{dv}{dx}

From equation (1),

v+x\frac{dv}{dx}=-\frac{x^2 + (vx)^2}{x^2 - x(vx)}

v+x\frac{dv}{dx}=-\frac{x^2 + v^2x^2}{x^2 - vx^2}

v+x\frac{dv}{dx}=-\frac{1 + v^2}{1 - v}

v+x\frac{dv}{dx}=\frac{1 + v^2}{v-1}

x\frac{dv}{dx}=\frac{1 + v^2}{v-1}-v

x\frac{dv}{dx}=\frac{1 + v^2-v^2+v}{v-1}

x\frac{dv}{dx}=\frac{v+1}{v-1}

\frac{v-1}{v+1}dv=\frac{1}{x}dx

Integrating both sides,

\int{\frac{v-1}{v+1}}dv=\int{\frac{1}{x}}dx

\int{\frac{v-1+1-1}{v+1}}dv=lnx + C

\int{1-\frac{2}{v+1}}dv=lnx + C

v-2ln(v+1)=lnx+C

Now, y = vx ⇒ v = y/x

\implies \frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C

5 0
2 years ago
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