Answer:
The lower bound of a 99% C.I for the proportion of defectives = 0.422
Step-by-step explanation:
From the given information:
The point estimate = sample proportion 


= 0.55
At Confidence interval of 99%, the level of significance = 1 - 0.99
= 0.01

Then the margin of error 



E = 0.128156
E ≅ 0.128
At 99% C.I for the population proportion p is: 
= 0.55 - 0.128
= 0.422
Thus, the lower bound of a 99% C.I for the proportion of defectives = 0.422
Answer:
Its F $1.75
Step-by-step explanation:
Because you add all the numbers up then once you get your answer you divided it by how many numbers there are like you'll get 8.75 divide it by 5 and you have your answer
P(P then C)=(7/10)(3/12)
P(PthenC)=21/120
P(PthenC)=7/40
Answer:
a
Step-by-step explanation:
Sometimes should be the answer