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4 years ago

12

The total attendance at a school play was 1250. The cost of tickets was $6.00 for students

1 answer:

daser333 [38]4 years ago

7 0

Answer:

look at picture

Step-by-step explanation:

x: student tickets

y: adult tickets

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Buy 20 ounces nuts puts equal amount of ounces in each of 3 bags. How many ounces nuts in each bag. Answer in whole number and a

satela [25.4K]

There will be 6 bags with a leftover of 2/3 ounces of nuts

7 0

3 years ago

A bucket contains 5 1/2 gallons of water. Water spills from the bucket so that only 5 pints remain.

Marysya12 [62]

Answer:

39

Step-by-step explanation:

There are 8 pints in a gallon, so 5 1/2 gallons is (5.5)(8 pints) = 44 pints.

If 5 remain, then 44-5 = 39 were spilled.

39 pints of water spilled from the bucket.

6 0

4 years ago

How many different integers can have the same absolute value

LUCKY_DIMON [66]

Integers are like -4,-3,-2,-1,0,1,2,3,4,5 etc

absolute value tells you how far the number is from 0

so example: |-5|=5=|5|

2 different integers can have the same absolute value
as long as they are negative of each other
like x and -x

6 0

4 years ago

Prove that sequence an = (3^n)/(2n)! is monotone

krek1111 [17]

When $n=1$ , you have $a_1=\dfrac3{2!}=\dfrac32$ .

When $n=2$ , you have $a_2=\dfrac{3^2}{4!}=\dfrac38$ .

Clearly, $a_1>a_2$ .

Assume $a_k$ . Now when $n=k+1$ , you have

$a_{k+1}=\dfrac{3^{k+1}}{(2k+2)!}=\dfrac3{(2k+2)(2k+1)}\times\dfrac{3^k}{(2k)!}=\dfrac3{(2k+2)(2k+1)}a_k$

Therefore by induction the sequence is monotone (decreasing).

5 0

3 years ago

(−t 4 −5t 3 −10t 2 )+(9t 3 +3t 2 −1)

klemol [59]

Answer:

$\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1$

Step-by-step explanation:

Given the expression

$\left(-t^4\:-5t^3\:-10t^2\:\right)+\left(9t^3\:+3t^2\:-1\right)$

Remove parentheses: (a)=a

$=-t^4-5t^3-10t^2+9t^3+3t^2-1$

Group like terms

$=-t^4-5t^3+9t^3-10t^2+3t^2-1$

Add similar elements

$=-t^4-5t^3+9t^3-7t^2-1$ ∵ $-10t^2+3t^2=-7t^2$

Add similar elements

$=-t^4+4t^3-7t^2-1$ ∵ $-5t^3+9t^3=4t^3$

Thus, the equivalent expression in simplified form:

$\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1$

4 0

3 years ago