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andreyandreev [35.5K]

2 years ago

14

What is the slope and y-intercept of the equation 5x + y = 4?

2 answers:

fenix001 [56]2 years ago

8 0

Answer:

Slope m=-5 Y intercept=4 (-5,4)

Step-by-step explanation:

To get the slope you will need Rise over Run. 5/1 which is slope

which will make x=0 and y=4 which is y intercept.

klio [65]2 years ago

6 0

Answer: Explanation:The slope-intercept form of a linear equation is: y=mx+bWhere m is the slope and b is the y-intercept value.We can subtract 5x from each side of the equation to put the equation in slope intercept form while keeping the equation balanced:−5x+5x+y=−5x+40+y=−5x+4y=−5x+4Therefore:The slope is: m=−5The y-intercept is: b=4 or (0,4)

Step-by-step explanation:

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Please help me on this i don’t get it that well

NeX [460]

Answer:

13.75

Step-by-step explanation:

make a ratio between the original lengths, 11 : 5.5

then put the ratio of the enlarged lengths, 27.5 : __

now you divide 27.5 by 11 to find how many times you multiplied the lengths, 2.5.

now you multiply 5.5 by 2.5 giving you the answer of 13.75

7 0

4 years ago

gretchen and henrik are meeting at a park. gretchen lives 2.4 miles away from the park and bikes at a constant rate of 12 miles

shepuryov [24]

1)t=S/U=2.4/12=0.2
2)t=S/U=8.4/36=0,23
3)0.23-0.2=0.03

6 0

3 years ago

Read 2 more answers

The length of line segment AG is 17 m and the line segment AD is 25 m. What is the length of line segment GD?

vladimir1956 [14]

Answer:

AG = 17 m

AD = 25 m

GD = ?

AD = AG + GD

GD = AD - AG

= 25 - 17

= 8 m

7 0

2 years ago

Read 2 more answers

Name this polynomial by its degree: 3x² + 5x-3

Stella [2.4K]

Answer:

$\boxed{\textsf {The given polynomial is a quadratic polynomial. }}$

Step-by-step explanation:

A polynomial is given to us and we need to make the polynomial by its degree . Here the given polynomial is 3x² + 5x -3 .

$\sf\implies p(x)= 3x^2+5x-3$

So here we can see that the highest power of the variable in the given polynomial is 2 . So the polynomial is a quadratic polynomial .

<u>★</u><u> </u><u>More </u><u>to </u><u>Know </u><u>:</u><u>-</u>

When we equate this quadratic polynomial with 0 , it becomes a quadratic equation.

That is ,

$\sf\implies p(x)= 3x^2+5x-3=0$

This is done in order to find the zeroes of the polynomial. The zeroes of the polynomial are the values for which the polynomial becomes 0 .

4 0

3 years ago

Read 2 more answers

What is the equation of the following line written in slope-intercept form -2/3 and -1/-4? y = -11x - 7 y = -7x + 11 y = -7x - 1

Snowcat [4.5K]

Answer:

$y=-7x-11$

Step-by-step explanation:

Given:

The two points on the line are $(-2,3)$ and $(-1,-4)$ .

The slope of the line joining two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given as:

$Slope,m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Here, $x_{1}=-2,y_{1}=3,x_{2}=-1,y_{2}=-4$

∴ $m=\frac{-3-4}{-1-(-2)}=\frac{-7}{-1+2}=\frac{-7}{1}=-7$

Equation of line with a point $(x_{1},y_{1})$ and slope $m$ is given as:

$y-y_{1}=m(x-x_{1})$

Plug in -2 for $x_{1}$ , 3 for $y_{1}$ and -7 for $m$ . This gives,

$y-3=-7(x-(-2))\\y-3=-7(x+2)\\y-3=-7x-(7\times 2)\\y-3=-7x-14\\y=-7x-14+3\\y=-7x-11$

Therefore, the equation of the line in vertex form is $y=-7x-11$ .

4 0

3 years ago