Answer:
The new volume is 2415 mL
Explanation:
The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases.
Boyle's law says that the volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure and is expressed mathematically as:
P * V = k
Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature is decreased, the gas pressure decreases. This can be expressed mathematically in the following way:

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

Having two different states, an initial state and an final state, it is true:

In this case:
- P1= 0.9 atm
- V1=4,600 mL= 4.6 L (being 1 L=1,000 mL)
- T1= 195 °C= 468 °K (being 0°C=273°K)
The final state 2 is in STP conditions:
- P2= 1 atm
- V2= ?
- T2= 0°C= 273 °K
Replacing:

Solving:

V2= 2.415 L =2,415 mL
<u><em>The new volume is 2415 mL</em></u>
Answer:
Name
Atomic Number
Atomic Symbol
Atomic Weight
Phase
Color
Classification
Group in Periodic Table
Group Name
Period in Periodic Table
Block in Periodic Table
Electronic Configuration
Melting Point
Boiling Point
Electronic Shell Structure
CAS Number
Neighborhood Elements
Lithium
3
Li
6.941
Solid
Silver
alkali metal
1
lithium family
2
s
[He] 2s1
180.54 °C
1342 °C
2, 1
CAS7439-93-2
Neighborhood Elements of Lithium
Cesium
55
Cs
132.90545
Solid
Silver
alkali metal
1
lithium family
6
s
[Xe] 6s1
28.44 °C
671 °C
2, 8, 18, 18, 8, 1
CAS7440-46-2
Neighborhood Elements of Cesium
Explanation:
4C₃H₅(NO₃)₃
------> 12CO₂
+ 6N₂
+ 10H₂O
+ O₂
mol of CO₂ = 
= 
mol ratio of CO₂ : C₃H₅(NO₃)₃
12 : 4
∴ if mole of CO₂ = 0.568 mol
then " " C₃H₅(NO₃)₃ = 
= 0.189 mol
∴ mass of nitroglycerin = mole * Mr
= 0.189 mol * 227.0995 g / mol
= 43.00 g