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d1i1m1o1n [39]
3 years ago
7

What is the molality of a solution that contains 75.2 grams of AgClO4 in 885 grams of benzene? Question 5 options: 0.41 m 4.10 m

8.20 m 0.83 m
Chemistry
1 answer:
SSSSS [86.1K]3 years ago
7 0
I took the test and got this question right! Here is the work.

molality = moles solute / kg solvent 

<span>moles AgClO4 = 75.2 g / 207.389 g/mol </span>
<span>= 0.3626 mol </span>

<span>molality = 0.6326 mol / 0.885 kg </span>
<span>= 0.410 m
The asnwer is 0.41.</span>
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