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joja [24]
3 years ago
9

Using molecular orbital theory, explain why the removal of one electron in O2 strengthens bonding, while the removal of one elec

tron in N2 weakens bonding?
Chemistry
1 answer:
Nuetrik [128]3 years ago
6 0
First you have a knowledge of bond order which is
 B.O=(no. of electrons in bonding orbital - no. of electrons in non-bonding orbital)÷2  
Note:
bond strength is directly proportional to bond order.
For oxygen:
B.O=(6-2)/2= 2; after the removal of two electrons(removal occur from non-bonding orbital)
B.O=(6-0)/2= 3 (As B.O increased bond strength increased)
For Nitrogen:
B.O=(6-0)/2= 3; after the removal of two electrons(removal occur from bonding orbital)
B.O=(4-0)/2= 2 (As B.O decreased bond strength decreased)

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Elena makes the table below to determine the number of atoms of each element in the chemical formula 3(NH4)2SO4
Hunter-Best [27]

Answer:

She should not have multiplied the nitrogen atom by subscript 2.

Explanation:

Chemical formula:

3(NH₄)₂SO₄

Elements present in given formula:

Nitrogen

Hydrogen

Sulfur

Oxygen

Total number of atoms of elements:

N = 3×1×2 = 6

H = 4×2×3 = 24

S = 1×3 = 3

O = 3×4 = 12

The number nitrogen atoms are six. Elena did mistake by counting the number of nitrogen. She should didn't multiplied the nitrogen atom by subscript 2.

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3 years ago
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a carbon-12 atom has a mass defect of 0.9564 amu. what is its nuclear binding energy? round to 3 significant figures.
emmasim [6.3K]

Answer:

Explanation:

A carbon-12 atom has a mass defect of 0.09564 amu. What is its nuclear binding energy? Round to 3 significant figures. x 10 J per carbon-12 atom

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Answer:

Object 4 in the example

Explanation:

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According to the second Newton's law, we know that force is directly proportional to both mass and acceleration. The equation representing this is F = ma.

Notice that all of them have the same acceleration. This means, the greater the mass, the greater the force for a fixed acceleration. Simply speaking, the forces for each of the objects would be 2a, 4a, 6a and 8a respectively.

Since we're interested in the magnitude of the force and not direction, we neglect whether acceleration is positive or negative. This means that object 4 will require the greatest force to move, as it has the greatest mass.

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