Answer:
Part A : y²(x + 2)(x + 4)
Part B: (x + 4) (x + 4)
Part C: (x + 4) (x - 4)
Step-by-step explanation:
Part A: Factor x²y²+ 6xy²+ 8y²
x²y²+ 6xy²+ 8y²
y² is very common across the quadratic equation , hence
= y² (x² + 6x + 8)
= (y²) (x² + 6x + 8)
= (y²) (x² + 2x +4x + 8)
= (y²) (x² + 2x)+(4x + 8)
= (y²) (x(x + 2)+ 4(x + 2))
= y²(x+2)(x+4)
Part B: Factor x² + 8x + 16
x² + 8x + 16
= x² + 4x + 4x + 16
= (x² + 4x) + (4x + 16)
= x( x + 4) + 4(x + 4)
= (x + 4) (x + 4)
Part C: Factor x² − 16
= x² − 16
= x² + 0x − 16
= x² + 4x - 4x - 16
= (x² + 4x) - (4x - 16)
= x (x + 4) - 4(x + 4)
= (x + 4) (x - 4)
Answer:
The area of the figure = 112 in²
Step-by-step explanation:
The figure consist of:
1) A square of side length of 10 in.
2) A right triangle with a base of (10 - 6 = 4 in) and a height of (16 - 10 = 6 in)
So,
The area of the square = (side length)² = 10² = 100 in²
The area of the triangle = 0.5 * height * base = 0.5 * 6 * 4 = 12 in²
So,
The total area = 100 + 12 = 112 in²
<u>The area of the figure = 112 in²</u>
Answer:
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Step-by-step explanation:
Answer:
2x +22
Step-by-step explanation:
3x + 10 - x + 12
Combine like terms
3x-x + 10+12
2x +22
If you hold it to an angle to a planar surface you will create ellipses....
