Answer:
Therefore, the probability is P=3/32.
Step-by-step explanation:
We know that Hiro has a stack of cards with one number from the set 1, 1, 2, 2, 3, 3, 3, 4 written on each card.
We calculate the probability that he pulls out a 3 first and then pulls out a 2 without replacing them.
The probability that he pulls out a 3 first is 3/8.
The probability of a second card being 2 is 2/8.
We get:
Therefore, the probability is P=3/32.
Answer:
Axis of symmetry
y-intercept
x-intercepts
Vertex
(I forgot the last one)
Step-by-step explanation:
Answer:
See below.
Step-by-step explanation:
a.
x = cost of adult ticket
y = cost of student ticket
cost of adult ticket is twice the cost of a student ticket
x = 2y
number of adult tickets = 64
number of student tickets = 132
cost of all adult tickets = 64x
cost of all student tickets = 132y
cost of all adult and student tickets combined: 64x + 132y
cost of all adult and student tickets combined: 1040
This gives us the equation:
64x + 132y = 1040
b.
Use substitution to solve the system of equations. Since x = 2y, where you see x in the second equation, substitute it with 2y.
64(2y) + 132y = 1040
128y + 132y = 1040
260y = 1040
y = 1040/260
y = 4
x = 2y = 2(4) = 8
adult ticket: $8
student ticket: $4
Using the left or right side of triangle, you can conclude that the midsegment will divide the triangle in both midlines of the sides. This means the length of the line would be half of the line below it. The equation would be:
47/4x+2= 94/ 4x+44
4x+44/ 4x+2 = 94/47
4x+ 44 / 4x+2 =2
4x+44 = 2(4x+2)
4x+44 = 8x+4
4x-8x= 4-44
-4x= -40
x= 10
Then the length of midline would be:
4x+2= 4(10)+2= 42
