Answer:
c) 100
Step-by-step explanation:
This is the best choice because the number is not too low or too high. He will get an accurate probability.
(b^4)^3
To simplify when something is raised to two different exponents, multiply the two exponents together:
4 * 3 = 12
You now have b^12.
The answer is D.
Answer:

Step-by-step explanation:
Given

Quadrant III
Required
Determine 
We have:

We know that:

This gives:


Collect like terms

Take LCM and solve


Take the square roots of both sides

Sin is negative in quadrant III. So:

Calculate 

We have: 
So:


Rationalize


So, we have:



Substitute: 

Take LCM

Answer:
The simplest form of 50/100 is 1/2
Answer: -7/8
Step-by-step explanation:
you need to find a common denominator for all of them
in this case it would be 24
2 18/24 -(- 1 12/24) + (-20/24) -(-9/24) - (+ 4 16/24)
2 18/24 + 1 12/24 - 20/24 + 9/24 - 4 16/24
4 6/24 - 20/24 + 9/24 - 4 16/24
3 10/24 + 9/24 - 4 16/24
3 19/24 - 4 16/24
- 21/24
-7/8