Answer:
solo suma todos los valores x+4(3)+(x+x)
en el segundo x+5(2)+x+3(2)
en el tercero x-3+(2x+5)+(2x+5)
y en el cuarto x(3)+(x+4)
Deacon Middle School
5x = number of boys
4x = number of girls
where x is some unknown number for now
(number of boys)+(number of girls) = 270 students total
5x+4x = 270
9x = 270
x = 270/9
x = 30
Since x = 30, this means
number of girls = 4x
number of girls = 4*30
number of girls = 120
There are 120 girls at Deacon Middle School
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Similarly, for Meadow Middle school
number of boys = 4y
number of girls = 5y
for some number y
(number of boys) + (number of girls) = 180 students total
4y+5y = 180
9y = 180
y = 180/9
y = 20
making,
number of girls = 5*y
number of girls = 5*20
number of girls = 100
so there are 100 girls at Meadow Middle School
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In summary so far, there are...
120 girls at Deacon Middle School
100 girls at Meadow Middle School
In total 120+100 = 220 girls from both schools
This is out of 270+180 = 450 students total
Divide the two values (220 and 450) to get
220/450 = 22/45
The final answer is 22/45
It cannot be reduced further as there are no common factors (other than 1) between 22 and 45
A pile of CD is 40 centimeters high
each CD is 8 millimeters
1 centimeter = 10 millimeters
40(10) = 400 millimeters high
400/8 = 50
50 CD in alll
hope this helps
Answer:
i)
ii)
And replacing we got:
![P(X \geq 3) = 1- [0.00317+0.0211+0.0669]= 0.90883](https://tex.z-dn.net/?f=%20P%28X%20%5Cgeq%203%29%20%3D%201-%20%5B0.00317%2B0.0211%2B0.0669%5D%3D%200.90883)
iii) 
Step-by-step explanation:
Let X the random variable of interest "number of inhabitants of a community favour a political party', on this case we now that:
The probability mass function for the Binomial distribution is given as:
Where (nCx) means combinatory and it's given by this formula:
Part i
We want this probability:
Part ii
We want this probability:
And we can use the complement rule and we have:

And if we find the individual probabilites we got:
And replacing we got:
![P(X \geq 3) = 1- [0.00317+0.0211+0.0669]= 0.90883](https://tex.z-dn.net/?f=%20P%28X%20%5Cgeq%203%29%20%3D%201-%20%5B0.00317%2B0.0211%2B0.0669%5D%3D%200.90883)
Part iii
We want this probability:

And replacing we got:
