Answer:
-2/-5
none of the option is correct
There are 14 chairs and 8 people to be seated. But among the 8. three will be seated together:
So 5 people and (3) could be considered as 6 entities:
Since the order matters, we have to use permutation:
¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆ x 3!
2,162,160 x 6 = 12,972,960 ways.
Another way to solve this problem is as follow:
5 + (3) people are considered (for the time being) as 6 entities:
The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways
So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:
Total number of permutation = 2,162,160 x 6 = 12,972,960
Answer
Sol: The correct answer is b. three planes that contain point B are ABD, AEF and DHF.
Answer:
x^2 +4x+4 = 4
Step-by-step explanation:
To complete the square take the coefficient of the x term
4
Divide by 2
4/2 =2
Square it
2^2 =4
Add it to both sides of the equation
x^2 +4x+4 = 4
Answer:
Allison worked 6 hours lifeguarding and 3 hours washing cars.
Step-by-step explanation:
Let
Number of hours Allison worked lifeguarding last week = x
Number of hours Allison worked washing cars last week = y
1. Last week Allison worked 3 more hours lifeguarding than hours washing cars hours, then
<u>Lifeguarding:</u>
$12 per hour
$12x in x hours.
<u>Washing cars:</u>
$8 pere hour
$8y in y hours.
2. Allison earned a total of $96, hence
You get the system of two equations:
Plot the graphs of these two equations (see attached diagram). These line intersect at point (6,3), so Allison worked 6 hours lifeguarding and 3 hours washing cars.
