Question 2

ANSWER NOW PLEASE.Solve this system of equations with substitution x = y - 4 2y = x

Arada [10]

In points form the answer is (-8,-4) and in equation form the answer is x=-8, y=-4
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4 0

3 years ago

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A student scored a 98, 86, 93 and 75 in math for the quarter. What is the student's math average for the quarter?

NNADVOKAT [17]

98+86+93+75=352

352/4=88

The math average is 88.

3 0

3 years ago

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You are working for a company that designs boxes, bottles and other containers. You are currently working on a design for a milk

ra1l [238]

Volume is a measure of the quantity of substance a given object can contain. The required answers are:

1.1 The volume of each milk carton is 360 $cm^{3}$ .

1.2 The area of cardboard required to make a single milk carton is 332.6 $cm^{2}$ .

1.3 Each carton can hold 0.36 liters of milk.

1.4 The cost of filling the 200 cartons is R 86.40.

The volume of a given shape is the amount of substance that it can contain in a 3-dimensional plane. Examples of shapes with volume include cubes, cuboids, spheres, etc.

The area of a given shape is the amount of space that it would cover on a 2-dimensional plane. Examples of shapes to be considered when dealing with the area include triangle, square, rectangle, trapezium, etc.

The box to be considered in the question is a cuboid. So that;

Volume of cuboid = length x width x height

Thus,

1.1 The volume of each milk carton = length x width x height

= 6 x 6 x 10

= 360

The volume of each milk carton is 360 $cm^{3}$ .

1.2 The total area of cardboard required to make a single milk carton can be determined as follows:

i. Area of the rectangular surface = length x width

= 6 x 10

= 60

Total area of the rectangular surfaces = 4 x 60

= 240 $cm^{2}$

ii. Area of the square surface = side x side = s²

= 6 x 6

Area of the square surface = 36 $cm^{2}$

iii. There are four semicircular surfaces, this implies a total of 2 circles.

Area of a circle = $\pi r^{2}$

where r is the radius of the circle.

Total area of the semicircular surfaces = 2 $\pi r^{2}$

= 2 x $\frac{22}{7}$ x $(3)^{2}$

= 56.57

Total area of the semicircular surfaces = 56.6 $cm^{2}$

Therefore, total area of cardboard required = 240 + 36 + 56.6

= 332.6 $cm^{2}$

The area of cardboard required to make a single milk carton is 332.6 $cm^{2}$ .

1.3 Since,

1 $cm^{3}$ = 0.001 Liter

Then,

360 $cm^{3}$ = x

x = 360 x 0.001

= 0.36 Liters

Thus each carton can hold 0.36 liters of milk.

1.4 total cartons = 200

Total volume of milk required = 200 x 0.36

= 72 litres

But, 1 kiloliter costs R1 200. Thus

Total volume in kiloliters = $\frac{72}{1000}$

= 0.072 kiloliters

The cost of filling the 200 cartons = R1200 x 0.072

= R 86.40

The cost of filling the 200 cartons is R 86.40.

For more clarifications on the volume of a cuboid, visit: brainly.com/question/20463446

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4 0

2 years ago

Drag each number to show whether it is equal to 90 percent, 90/100,or neither

victus00 [196]

9%= 9/100
9/10= 90%
.9= 90%
90/10= other
.9%= other
.09= 9/100

7 0

3 years ago

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Consider line A whose equation is y = -10x + 8. If line B is perpendicular to line A and has a y-intercept at y = 3, what is the

r-ruslan [8.4K]

Answer:

C) . y=(1/10)x+3

Step-by-step explanation:

Given the equation of the line is y=-10x+8

It is in the form of y=mx+c where m is the slope of the line. Now on comparision we get m1=-10.

We knoew that two lines are perpendicular iff the product of their slopes is equal to -1.

$m1*m2=-1$

the slope of the recquired line = $\frac{-1}{-10}$ = $\frac{1}{10}$

The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept

Given the y intercept of the recquired line (b)=3

The recquired line is

y=mx+b

y=(1/10)x+3

7 0

3 years ago