8. The length of the support is 7. 9 m
9. The length of the conveyer is 12m
3. a = 59m
A = 44°
B = 52°
4. c = 88. 6 mm
b = 49. 1 m
B = 34°
<h3>How to solve the trigonometry</h3>
8. We have the angle to be 20 degrees
Opposite side = x
hypotenuse = 23m
Using the sine ratio
sin θ = opposite/ hypotenuse

Cross multiply
× 
× 
x = 7. 9 m
The length of the support is 7. 9 m
9. The angle of elevation is 37. 3 degrees
Hypotenuse = 19 . 0m
Opposite = x
Using the sine ratio
sin θ = opposite/ hypotenuse

cross multiply
× 
x = 11.5
x = 12 m in 2 significant figures
The length of the conveyer is 12m
3. To determine the sides and angles, we use the sine rule;

For side a, we use the Pythagorean theorem




a = 58. 58, a = 59m
To find angle A and B, use the sine rule

cross multiply
×
=
× 
make sin A subject of formula


A = 
A = 44°

cross multiply
×
=
× 
make sin b subject of formula


B = 
B = 52°
4. To find the sides, we use the sine rule;

Cross multiply
×
× 
make 'c' subject of formula

c = 88. 6 mm
To find length b, we use the Pythagorean theorem




b = 49. 1 m

cross multiply

B = 
B = 34°
Learn more about trigonometric identity here:
brainly.com/question/7331447
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