Step-by-step explanation:
1. if the number of pages in the 1st day is 'x', then the 2d day - 'x+10', the 3d day - 'x+20', the 4th day - 'x+30', the 5th day - 'x+40' and the last day - 'x+50' pages;
2. if the sum of all the pages is 300, then it is possible to make up the equation:
x+x+10+x+20+x+30+x+40+x+50=300;
3. x=25, it means:
1st day - 25;
2d day - 35;
3d day - 45;
4th day - 55;
5th day - 65;
6th day - 75 pages.
Answer:
x = 40
Step-by-step explanation:
5x + 900 = 1100
=> 5x = 1100 - 900
=> 5x = 200
=> x = 40
Hoped this helped.
Answer: B
Step-by-step explanation:
Uh... nothing much to say for this one. When you divide with fractions, you always flip the second number. 1/2 flipped is 2/1, or 2. So the final problem is 50x2, which is 100. And yeah, that's all I have to say...
Answer:
So the equation in standard form will be
Step-by-step explanation:
We have given equation 
We have to write this expression in standard form
For writing in standard form first we have to do operation on the expression
We know that there is property of exponent that when two functions are multiplied with each other then there exponent are added
So 
So the equation in standard form will be 
Answer:
Number of bulbs which can be lit using 1 kg of coal = 9
Step-by-step explanation:
Energy yielded by burning 1 kg of coal = 30 × 106 joules
= 3180 joules
Amount of energy that can be used for electricity = 30 % of 3180 joules
= 0.30 × 3180
= 954 joules
Energy needed for lighting one bulb = Wattage of bulb × No. of hours of lighting
⇒ Energy needed for lighting one bulb = 100 × 1
= 100 joules

Hence, Number of bulbs which can be lit using 1 kg of coal = 9