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Zina [86]
3 years ago
11

2x = 64 (Enter the X)

Mathematics
1 answer:
Maru [420]3 years ago
4 0

Answer:

x=32

Step-by-step explanation:

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Select the equivalent expression . ( 3^ 6 y^ -5 )^ 2 =?
Basile [38]

Answer:

C. 3¹² y¹⁰

Step-by-step explanation:

(3⁶/y⁻⁵)² = (3⁶/1 / 1/y⁵)² = (3⁶ *y⁵)² = 3¹² y¹⁰

6 0
2 years ago
Each ticket for a concert cost $14.
Rudik [331]
$8792 / $14 = 628 tickets were sold
8 0
3 years ago
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The speed of light is about 300,000 kilometers per second. The Sun is about 93 million miles from Earth. How many minutes does i
spin [16.1K]

Answer: 8.3 minutes

Step-by-step explanation:

1 mile is to 1.60934km so 93 million miles is:

= 93 * 1.609

= ‭149,637,000‬ km

Travelling at 300,000 km per second, the number of seconds it takes is:

= ‭149,637,000‬/300,000

= ‭498.79‬ secs

In minutes this is:

= ‭498.79‬/60

= 8.3 minutes

4 0
3 years ago
I need help on a McGraw hill assignment its due soon pls help.
blagie [28]

Answer:

1850

Step-by-step explanation:

The problem is asking you how many kids (predicted by the superintendent) will buy lunches for 1-2 days. Since you know the percentage predicted and the student amount, just multiply as a decimal (convert by putting the number over 100 as a fraction.)

5000*0.37=1850

4 0
2 years ago
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Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.
Mice21 [21]

Answer:

<em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

Step-by-step explanation:

Making factors of 8y^{6}+ 144y^{5}+ 640y^{4}

Taking 8y^{4} common:

\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)

Using <em>factorization</em> method:

\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times  4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)

Now, Making factors of 2y^{4} + 40y^{3} + 200y^{2}

Taking 2y^{2} common:

\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)

Using <em>factorization</em> method:

\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10)        ............ (2)

The underlined parts show the Highest Common Factor(HCF).

i.e. <em>HCF</em> is 2y^{2} (y+ 10).

We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:

HCF \times LCM = p \times q

Using equations <em>(1)</em> and <em>(2)</em>: \Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)

Hence, <em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

5 0
3 years ago
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