It is important to note that all the information's required are already given in the question
Probability that a day will be hot = 0.15 + 0.10
= 0.25
Probability that a day will be sunny = 0.15 + 0.30 + 0.10
= 0.55
Adding the above two probabilities, we get = 0.25 + 0.55
= 0.80
Now
Probability that a day will be both hot and sunny = 0.15
So
Probability that a day was hot or sunny = 0.80 - 0.15
= 0.65
I hope the procedure is clear enough for you to understand.
Answer:B
I think we are in the same class lol
Step-by-step explanation:448 divided by 14= 32
448 divided by 16= 28
B=speed of boat in water
Y= Speed of current
B+y=32
B-y=28
32 + 28 =60
60 divided by 2 = 30
32 -30 =2
B=30
Y=2
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Answer: Can I see the whole questions?
Step-by-step explanation:
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )
<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))
<em>z</em> = (-3 - 3<em>i </em>) / 2
Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have
arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>
arg(<em>z</em>) = arctan(1) - <em>π</em>
arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>
arg(<em>z</em>) = -3<em>π</em>/4
where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.
Answer is A or your first option.
