The value of two arithmetic means which are inserted between 3 and 24 are 24/9 and 75/9.
<h3>What is arithmetic mean?</h3>
Arithmetic mean is the mean or average which is equal to the ratio of sum of all the group numbers to the total numbers.
The two arithmetic means between 3 and 24 are has to be inserted.
3, A₂, A₃, 24
All the four numbers are in arithmetic progression. The nth terms of AM can be found using the following formula:
t(n)=a(n-1)d
Here, d is the common difference a is the first terms and n is the total term. The first term, a=3 and t₄=24. Thus, the common difference is;
The second and 3rd term are:
Thus, the value of two arithmetic means which are inserted between 3 and 24 are 24/9 and 75/9.
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The common difference of the sequence is -3 and the fifth term is 5
<h3>How to determine the common difference?</h3>
The sequence is given as:
17, 14, 11, 8....
The common difference is
d = T2 - T1
So, we have
d = 14 - 17
Evaluate
d = -3
Hence, the common difference of the sequence is -3
<h3>How to determine the
fifth term?</h3>
The fifth term is calculated as:
T5 = a + 4d
Where
a = T1 = 17
d = -3
So, we have:
T5 = 17 - 4 * 3
Evaluate
T5 = 5
Hence, the fifth term is 5
<h3>How to determine the
nth term?</h3>
The nth term is calculated as:
Tn = a + (n - 1)d
Hence, the nth term is Tn = a + (n - 1)d
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Answer:
19
Step-by-step explanation:
f(x) = 3x^2-3x + 1
Let x = -2
f(-2) = 3( -2)^2-3*-2 + 1
= 3 * 4+6+1
= 12 +6+1
= 19
Answer:
It's the first one
Step-by-step explanation:
All you gotta do is add the value of p with the value of q
