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3 years ago

9

If you spend 600 rupees per month, that is the amount of loan in 6 months. If he spends 440 rupees per month, he repays the loan

in 9 months. So what is the monthly income?

1 answer:

Marta_Voda [28]3 years ago

8 0

Answer:

hjskkdoododkdkdndndndndndndndnsn sorry I needed points to ask a question

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I need help if you answer this your littearly a pro hacker pls

Anit [1.1K]

Answer:

24 meters cubed

HOPE THIS HELPS

- Todo ❤️

Step-by-step explanation:

V=Bh

V=6*4

V=24

6 0

2 years ago

Read 2 more answers

Match the three dimensional figure to its volume based on the given dimensions assume n= 3,14.

stepan [7]

Answer:

Volume of right cylinder= 150.72 cu cm

Volume of cone= 314.159 cu cm

Volume of pyramid with base area 16= 160 cu cm

Volume of pyramid with length 3 =48 cu cm

Step-by-step explanation:

Volume of right cylinder = πr²h= 22/7 (4)²3= 150.72 cu cm

Volume of a cone = 1/3 πr²h= 1/3 (22/7) (5)²(12)= 314.159 cu cm

Volume of a pyramid = 1/3 ah= 1/3(16) (30)= 160 cu cm (where a= area and h= height)

Volume of pyramid= 1/3 (3*3)(16)= 48 cu cm

6 0

3 years ago

+ x = 12 – 2x<br> what is this?

AleksAgata [21]

Answer:

x= -6

Step-by-step explanation:

7 0

2 years ago

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List angles in order from smallest to largest

shepuryov [24]

Answer:

∠S, ∠R, ∠T

Step-by-step explanation:

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2 years ago

X²+y²-6x+14y-1=0<br> and please show your work so I can learn

Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

$x^2 + y^2 -6x+14y-1=0$

We need to use the Quadratic Formula*

$x =\frac{-b+\sqrt{b^2}-4ac }{2a}$ , $\frac{-b-\sqrt{b^2} -4ac }{2a}$

Thus, given the problem:

$a = 1, b=-6, c=y^2+14y-1$

So now we just need to plug them in the Quadratic Formula*

$x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$ , $x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$

As you can see, it is a mess right now. Therefore, we need to simplify it

$x=\frac{6+2\sqrt{10-y^2-14y} }{2}$ , $x = \frac{6-2\sqrt{10-y^2-14y} }{2}$

Now that's get us to the final solution:

$x=3+\sqrt{10-y^2-14y}$ , $x=3-\sqrt{10-y^2-14y}$

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

3 0

2 years ago