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2 years ago

What is the value of the expression below when y = 5?

Mathematics

2 answers:

chubhunter [2.5K]2 years ago

6 0

Answer:

Basically, you need to plug 5 in as y

Step-by-step explanation:

First, plug 5 in the place of Y 10 * 5 + 6

Then solve the equation from there.

10 * 5 = 50

50 + 6 = 56

muminat2 years ago

3 0

Answer:

Step-by-step explanation:

10y+6

10(5)+6

10*5=50

50+6=56

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Solve f 10/f = 36/90 f = ?

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3 years ago

Consider independent simple random samples that are taken to test the difference between the means of two populations. The varia

Arturiano [62]

Answer:

d. t distribution with df = 80

Step-by-step explanation:

Assuming this problem:

Consider independent simple random samples that are taken to test the difference between the means of two populations. The variances of the populations are unknown, but are assumed to be equal. The sample sizes of each population are n1 = 37 and n2 = 45. The appropriate distribution to use is the:

a. t distribution with df = 82.

b. t distribution with df = 81.

c. t distribution with df = 41.

d. t distribution with df = 80

Solution to the problem

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

And the statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

This last one is an unbiased estimator of the common variance $\sigma^2$

So on this case the degrees of freedom are given by:

$df= 37+45-2=80$

And the best answer is:

d. t distribution with df = 80

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

Koto’s average velocity along her route was 4. 5 m/s. She started at her house and traveled 15,000 meters north, 5,000 meters ea

Lostsunrise [7]

The time taken for her trip is 3 hours.

<h3>Given that</h3>

Koto’s average velocity along her route was 4. 5 m/s.

She started at her house and traveled 15,000 meters north, 5,000 meters east, 20,000 meters south, and then 5,000 meters west.

<h3>We have to determine</h3>

What was the time of her trip?

<h3>According to the question</h3>

She started at her house and traveled 15,000 meters north, 5,000 meters east, 20,000 meters south, and then 5,000 meters west.

<h3 /><h3>The calculation of such a trip of Koto can be done by applying the known formula of Time when the Speed is multiplied by Distance to compute the actual time of the trip.</h3>

The formula to calculate the time for her trip is;

$\rm Speed = \dfrac{ Distance}{Time}\\
\\
Time = \dfrac{Distance}{Speed}\\
\\
$

Using the formula above, the commute in each direction is added as 45000 meters or 45 kilometers.

If Koto's average speed is 4.5 meters per second, then she travels roughly 270 meters in one minute.

Substitute all the values in the formula;

$\rm\ Time = \dfrac{Distance}{Speed}\\\\ Time = \dfrac{45000}{270}\\
\\
Time =166.7$

Converting minutes into hours,

$\rm Hours = \dfrac{Minute}{60}\\
\\
Hours = \dfrac{166.7}{60}\\
\\
Hours = 2.77 \\
\\
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Hence, the time taken for her trip is 3 hours.

To know more about Time and Distance click the link given below.

brainly.com/question/4433818

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2 years ago