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Travka [436]
2 years ago
15

What is the value of the expression below when y = 5?

Mathematics
2 answers:
chubhunter [2.5K]2 years ago
6 0

Answer:

Basically, you need to plug 5 in as y

Step-by-step explanation:

First, plug 5 in the place of Y 10 * 5 + 6

Then solve the equation from there.

10 * 5 = 50

50 + 6 = 56

muminat2 years ago
3 0

Answer:

56

Step-by-step explanation:

10y+6

10(5)+6

10*5=50

50+6=56

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In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that
attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable X\sim Poisson(\lambda = 0.62).

The probability function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

             = 1 - P (X = 0) - P (X = 1)

             =1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: \lambda=7\times0.62=4.34

Compute the probability of no deaths in a corps over 7 years as follows:

P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0
2 years ago
I’m supposed to simplify; however, I’m absolutely clueless on how to simplify a radical. Can anyone help?
anyanavicka [17]
Your answer simplified should be
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7 0
3 years ago
Read 2 more answers
How do you find DE, Round to nearest 10th
Sergeu [11.5K]

Answer:  DE\approx6.0

Step-by-step explanation:

Observe in the figure given in the exercise that four right triangles are formed.

In this case you can use the following Trigonometric Identity to solve this exercise:

cos\alpha=\frac{adjacent}{hypotenuse}

From the figure you can identify that:

\alpha =53\°\\\\hypotenuse=10\\\\adjacent=BE=DE

Then, you can substitute values:

cos(53\°)=\frac{DE}{10}

The next step is to solve for DE in order to find its value. This is:

10*cos(53\°)=DE\\\\DE=6.01

Finally, rounding the result to the nearest tenth, you get that this is:

DE\approx6.0

7 0
3 years ago
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